>>12044799we extend the reals to the complex numbers by taking the real numbers R
and then adding a solution to x^2 + 1
this is written R[x]/(x^2+1)
if we want to add 1/0 in, we would do
R[x] / (0x-1) = R[x] / (-1)
this is called a quotient ring, and in this case, dividing by (-1) forces everything inside of it to become the same as each other
so the only thing in R[x]/(-1) is one thing, namely its all 1/0
which is why its not an interesting thing to add in
in your case 3.4 + 5i - 2n, would again all just collapse into n = 1/0
1/0 is called an absorbing element, since it absorbs everything
like multiplying by 0 just absorbs everything into it
