/sci/ - Science & Math » Thread #12020780

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Anonymous Tue 18 Aug 10:29:06 2020 No.12020780 View Reply Original Report

Quoted By: >>12020787 >>12020823

Can someone solve this step by step on paper?

Anonymous

Anonymous Tue 18 Aug 2020 10:33:25 No.12020786 Report

Quoted By:

I can do it by induction

Anonymous

Anonymous Tue 18 Aug 2020 10:33:50 No.12020787 Report

Quoted By: >>12020790 >>12020795

>>12020780

> Reminder: /sci/ is for discussing topics pertaining to science and mathematics, not for helping you with your homework or helping you figure out your career path.

>If you want advice regarding college/university or your career path, go to /adv/ - Advice.

>If you want help with your homework, go to /wsr/ - Worksafe Requests.

This might not be your homework but I think this belongs on /wsr/

Anonymous

Anonymous Tue 18 Aug 2020 10:34:53 No.12020790 Report

Quoted By:

>>12020787
>>>/wsr/

Anonymous

Anonymous Tue 18 Aug 2020 10:37:36 No.12020795 Report

Quoted By: >>12020800 >>12020801 >>12020803

>>12020787
Yeah I know but I need someone to explain this to me real quick, step by step just so I can use it in further examples

Anonymous

Anonymous Tue 18 Aug 2020 10:39:56 No.12020800 Report

Quoted By:

>>12020795
For what? (Just curious)

Anonymous

Anonymous Tue 18 Aug 2020 10:40:07 No.12020801 Report

Quoted By:

>>12020795
It’s convergent so you can split it up.

Anonymous

Anonymous Tue 18 Aug 2020 10:40:14 No.12020803 Report

Quoted By:

>>12020795
Dude fuck off.

Anonymous

Anonymous Tue 18 Aug 2020 10:51:08 No.12020823 Report

Quoted By: >>12020850 >>12020865 >>12020923 >>12021586 >>12021628 >>12022293

>>12020780
$\sum_{n=1} \left(\frac{-1}{9}\right)^n+\left(\frac{1}{3}\right)^n\\<br />=-2+\sum_{n=0} \left(\frac{-1}{9}\right)^n+\left(\frac{1}{3}\right)^n\\<br />=-2+\frac{1}{1+\frac{1}{9}}+\frac{1}{1-\frac{1}{3}}\\<br />=-2+\frac{9}{10}+\frac{3}{2}=\frac{2}{5}<br />$

Anonymous

Anonymous Tue 18 Aug 2020 11:05:17 No.12020850 Report

Quoted By:

>>12020823
Nice.

Anonymous

Anonymous Tue 18 Aug 2020 11:16:59 No.12020865 Report

Quoted By: >>12020884

>>12020823
Retard he said to solve it on paper

Anonymous

Anonymous Tue 18 Aug 2020 11:25:06 No.12020884 Report

Quoted By:

>>12020865
But he didn't say I should take a picture and post it

Anonymous

Anonymous Tue 18 Aug 2020 11:43:48 No.12020923 Report

Quoted By: >>12020928 >>12020953

>>12020823
Where did the -2 come from? Summing from 0 to 1 gives 2.2222...

Anonymous

Anonymous Tue 18 Aug 2020 11:47:39 No.12020928 Report

Quoted By: >>12020938 >>12020951

>>12020923
You need to sum from 0 to 0.

Anonymous

Anonymous Tue 18 Aug 2020 11:55:42 No.12020938 Report

Quoted By: >>12020950

>>12020928
Doesn't make any sense. I guess it's because I'm using the integral summation rule. What's the equivalent rule in discrete summation?

Anonymous

Anonymous Tue 18 Aug 2020 12:02:32 No.12020950 Report

Quoted By:

>>12020938
Sum from zero to infinity is equal to value at zero plus sum from one to infinity?

Anonymous

Anonymous Tue 18 Aug 2020 12:02:36 No.12020951 Report

Quoted By:

>>12020928
I guess it does make sense now that I think about it. Discrete summation is just adding up terms in a series where you can remove individual terms while integration has to happen in an interval.

Anonymous

Anonymous Tue 18 Aug 2020 12:03:24 No.12020953 Report

Quoted By:

>>12020923
You only need the partial sum of n=0 which is 2

Anonymous

Anonymous Tue 18 Aug 2020 15:51:55 No.12021586 Report

Quoted By:

>>12020823
big brain

Anonymous

Anonymous Tue 18 Aug 2020 16:08:15 No.12021628 Report

Quoted By:

>>12020823
is this supposed to be calculus?

Anonymous

Anonymous Tue 18 Aug 2020 18:59:54 No.12022293 Report

Quoted By:

>>12020823
this. whenever you see exponents the first thing you try is the geometric series

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