/sci/ - Science & Math » Thread #11979271

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Anonymous Thu 06 Aug 03:02:37 2020 No.11979271 View Reply Original Report

Quoted By: >>11979277 >>11979281 >>11979286

What's wrong with the following?

$ \left (-1 \right )^2 = 1^2 \sqrt{\Left (-1 \Right )^2} = \sqrt{1^2} -1 = 1 $

Anonymous

Anonymous Thu 06 Aug 2020 03:03:32 No.11979277 Report

Quoted By:

>>11979271
$ \left (-1 \right )^2 = 1^2 \newline \sqrt{\left (-1 \right )^2} = \sqrt{1^2} \newline -1 = 1 $

Anonymous

Anonymous Thu 06 Aug 2020 03:04:49 No.11979281 Report

Quoted By:

>>11979271
$ \left (-1 \right )^2 = 1^2 \sqrt{\left (-1 \right )^2} = \sqrt{1^2} -1 = 1 $

Anonymous

Anonymous Thu 06 Aug 2020 03:07:39 No.11979286 Report

Quoted By: >>11979524 >>11979528 >>11979533 >>11980253

>>11979271
$ \left (-1 \right )^2 = 1^2 \\ \sqrt{\left (-1 \right )^2} = \sqrt{1^2} \\ -1 = 1 $

Wtf why aren't my newlines appearing

Anonymous

Anonymous Thu 06 Aug 2020 04:59:39 No.11979524 Report

Quoted By:

>>11979286
-1 squared is 1, sqrt 1 is 1
sqrt of -1 is i, i squared is -1
negative one is not equal to one

Anonymous

Anonymous Thu 06 Aug 2020 05:01:27 No.11979528 Report

Quoted By:

>>11979286
sqrt((-1)^2) =/= -1

El Arcón

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El Arcón Thu 06 Aug 2020 05:02:53 No.11979533 Report

Quoted By: >>11980239

>>11979286
use "eqn" tag instead of "math" with double slash line break and tex checker tool

Anonymous

Anonymous Thu 06 Aug 2020 11:16:43 No.11980239 Report

Quoted By:

>>11979533
I was. The \\ fixed the problem.

Anonymous

Anonymous Thu 06 Aug 2020 11:23:29 No.11980253 Report

Quoted By: >>11980254 >>11980356

>>11979286
x^2 is not monotonic

Anonymous

Anonymous Thu 06 Aug 2020 11:25:33 No.11980254 Report

Quoted By: >>11980282

>>11980253
so?

Anonymous

Anonymous Thu 06 Aug 2020 11:48:01 No.11980282 Report

Quoted By: >>11980356 >>11980669

>>11980254
so you can't just do
f(x1) = f(x2) => x1 = x2

Anonymous

Anonymous Thu 06 Aug 2020 12:22:13 No.11980356 Report

Quoted By:

>>11980253
>>11980282
It doesn't have to be monotonic. For example f(x)=x, x<=0 and 1/x, x>0 is increasing in the negatives and decrasing in the positives, but it is true that for every x1,x2 if f(x1)=f(x2) then x1=x2

Anonymous

Anonymous Thu 06 Aug 2020 14:51:54 No.11980669 Report

Quoted By:

>>11980282
Where am I making a statement like that?

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