/sci/ - Science & Math » Thread #11952523

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Anonymous Thu 30 Jul 10:26:38 2020 No.11952523 View Reply Original Report

Quoted By: >>11952525 >>11952535 >>11952659 >>11953038 >>11953161 >>11953937 >>11954134

Proof that photons do have mass

Photon with wave length $\lambda$ has energy $E = \frac{\hbar c}{\lambda}$

Einstein says $E = mc^2$

Therefore $m = \frac{\hbar}{c \lambda} \neq 0$

Anonymous

Anonymous Thu 30 Jul 2020 10:28:26 No.11952525 Report

Quoted By:

>>11952523
what is the speed of photons in that snout?

Anonymous

Anonymous Thu 30 Jul 2020 10:32:37 No.11952535 Report

Quoted By:

>>11952523
Apparently there's a longer version of einstein's equation that accounts for photons. I still think photons are crazy as hell though.

Anonymous

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Anonymous Thu 30 Jul 2020 11:16:00 No.11952659 Report

Quoted By: >>11952872

>>11952523
An object that moves at the speed of light cannot have any mass.
E = MC^2 only accounts for stationary objects and photons cannot be stationary.
Fucking degenerates.

Anonymous

Anonymous Thu 30 Jul 2020 11:55:48 No.11952872 Report

Quoted By: >>11952914

>>11952659
Use the photons frame of reference. Within that frame photons are stationary. What now?

Anonymous

Anonymous Thu 30 Jul 2020 12:00:43 No.11952914 Report

Quoted By: >>11952937 >>11953050

>>11952872
photon doesn't have a frame of reference

Anonymous

Anonymous Thu 30 Jul 2020 12:03:12 No.11952937 Report

Quoted By: >>11952944

>>11952914
Of course they have, you got served.

Anonymous

Anonymous Thu 30 Jul 2020 12:04:12 No.11952944 Report

Quoted By:

>>11952937
prove it

Anonymous

Anonymous Thu 30 Jul 2020 12:08:14 No.11952970 Report

Quoted By:

What is this brainlet conclusion

Anonymous

Anonymous Thu 30 Jul 2020 12:27:21 No.11953038 Report

Quoted By:

>>11952523
E=mc^2 = approximation only for stationary state.
When a particle moves, E > E0.
Photon's "rest mass" = 0, but photon doesn't rest.

Anonymous

Anonymous Thu 30 Jul 2020 12:28:37 No.11953050 Report

Quoted By: >>11953197

>>11952914
Just do a Lorentz transformation with v=c. If anything diverges replace it by -1/12 and call it "analytic continuation". Problem solved.

Anonymous

Anonymous Thu 30 Jul 2020 12:52:55 No.11953161 Report

Quoted By:

>>11952523
This is what we call the schrodinger paradox.

Anonymous

Anonymous Thu 30 Jul 2020 12:57:40 No.11953197 Report

Quoted By:

>>11953050
You're applying Barnett's identity wrong. It does not work for series like 1-1+1-1+1...

Anonymous

Anonymous Thu 30 Jul 2020 17:24:27 No.11953937 Report

Quoted By: >>11954092

>>11952523
No retard, Einstein says:
$E^2 = m^2 c^4 + p^2 c^2$

Anonymous

Anonymous Thu 30 Jul 2020 18:18:04 No.11954092 Report

Quoted By:

>>11953937
E
? pc
mc2

Anonymous

Anonymous Thu 30 Jul 2020 18:29:59 No.11954134 Report

Quoted By:

>>11952523
It's h not h bar

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