>>11930632theres one way to get 75, one combination
out of how many combinations?
6 bills, how many sets of 3, order irrelevent, are there? from each bill, there are 5 choices of second bill. and four choices of third bill. so 120 combos. but we thresh overlaps, how? well, for each combo of 3, there are 6 ways to achieve it. having all the combos, there are 6 copies of each. this means we need 1/6th the copies, 120/6=20.
1/20 chance. am i right?
