/sci/ - Science & Math » Thread #11876020

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Anonymous Tue 07 Jul 04:22:18 2020 No.11876020 View Reply Original Report

Quoted By: >>11876570 >>11876668 >>11885690

Thoughts?

Anonymous

Anonymous Tue 07 Jul 2020 04:55:58 No.11876111 Report

Quoted By:

Isn't there an easy way to integrate the perimeter or something?

Anonymous

Anonymous Tue 07 Jul 2020 08:36:45 No.11876570 Report

Quoted By: >>11876668 >>11876705 >>11877025

>>11876020
This process doesn't give you a circle. It gives you a collection of points which are close to a circle, but which do not have a fixed distance from the center point.

Anonymous

Anonymous Tue 07 Jul 2020 09:44:04 No.11876668 Report

Quoted By:

>>11876020
It's pi in the L1 metric, no troll here

>>11876570
It's fixed distance in L1

Anonymous

Anonymous Tue 07 Jul 2020 10:03:32 No.11876705 Report

Quoted By:

>>11876570
step five is only approximate, but it's closer than i thought it would be. The length and width is 100% accurate, it's just not quite the hypotenuse we want

Anonymous

Anonymous Tue 07 Jul 2020 10:13:52 No.11876723 Report

Quoted By: >>11876741 >>11882409

Is there a law for slack and drop in a string?

Anonymous

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Anonymous Tue 07 Jul 2020 10:23:06 No.11876741 Report

Quoted By: >>11876777

>>11876723
Limit is x or 2x?

Anonymous

Anonymous Tue 07 Jul 2020 10:50:17 No.11876777 Report

Quoted By: >>11877072

>>11876741
lol, minimum is x for 2x with L=0

On paper x=2.3 for 2x = 1 with L=10

Anonymous

Anonymous Tue 07 Jul 2020 13:04:34 No.11877025 Report

Quoted By:

>>11876570
There is a few other knowns, the slope starts at (1,-1) from the bottom left square corner, tracks through (1,0), and finishes at (1,1)

Second derivative is probably a constant, since the rate of change is smooth

Anonymous

Anonymous Tue 07 Jul 2020 13:30:38 No.11877072 Report

Quoted By:

>>11876777
more x2=1's
x=1.8, L=5
x= 3.3 L=20
x = 4.7 L=40

Anonymous

Anonymous Tue 07 Jul 2020 14:26:02 No.11877263 Report

Quoted By: >>11879094

Can't we do (1,1) + (1,0) to (1,0.5) + (1,0.5)
(sqrt(2) + 1) /2 =1.2071 to sqrt(1.25) = 1.1180

(1.2071 + 1.1180) / 2 = 1.1625
1.1625 * sqrt(2) * 4 = 6.57

Anonymous

Anonymous Tue 07 Jul 2020 23:56:18 No.11879094 Report

Quoted By: >>11879113

>>11877263
(1,1) + (1,0.5) to (1,0.5) + (1,0)
(sqrt(2) + sqrt(1.25)) /2 = 1.266
(1 + sqrt(1.25)) /2 = 1.059

(1.266+1.059)/2 = 1.1625

Anonymous

Anonymous Wed 08 Jul 2020 00:05:27 No.11879113 Report

Quoted By: >>11880772

>>11879094

(1,1) + (1,0.5) = (1,0.75)
(1,0) + (1,0.5) = (1,0.25)

(1,0.75) = sqrt(1^2 + 0.75^2) = 1.25
(1,0.25) = sqrt(1^2 + 0.25^2) = 1.03

quarter pi (est) = 1.1403
perimeter est = 6.45

Anonymous

Anonymous Wed 08 Jul 2020 13:14:40 No.11880772 Report

Quoted By: >>11880810

>>11879113
(1,1) = 1.41
(1,0.75) = 1.25

(1,0.25) = 1.03
(1,0) = 1

1.33 * 0.25 + 1.1403 * 0.5 + 1.015*0.25 = 1.1564

Anonymous

Anonymous Wed 08 Jul 2020 13:35:43 No.11880810 Report

Quoted By:

>>11880772
Finding location (1,0.1)
[0.9x, 0.05y] ?

sqrt(0.1^2 + 0.95^2) = 0.955

Anonymous

Anonymous Thu 09 Jul 2020 00:46:23 No.11882409 Report

Quoted By: >>11883971

>>11876723
cosh (hyperbolic cos)
unless it was a rhetorical question somehow related to OP's q

Anonymous

Anonymous Thu 09 Jul 2020 16:01:57 No.11883971 Report

Quoted By:

>>11882409
> In mathematics, hyperbolic functions are analogs of the ordinary trigonometric functions defined for the hyperbola rather than on the circle: just as the points form a circle with a unit radius, the points form the right half of the equilateral hyperbola.

Pythagoras triangles back to back work for a single point tension

Did you like the iterative Pi solution?

Anonymous

Anonymous Fri 10 Jul 2020 02:21:37 No.11885686 Report

Quoted By:

It looks like it converges on 3.24
What went wrong?

Anonymous

Anonymous Fri 10 Jul 2020 02:22:14 No.11885690 Report

Quoted By:

>>11876020
no, brain empty

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