>>11711709Calculator: three calculators equals 30, each calculator is 10. The numbers inside the calculator are 1234, which adds up to 10. Therefore, we can assume that the altered calculator in the last line is worth 9.
As for the clocks, the first two are on 9 o'clock, and the last on 3 o'clock. This is 9+9+3 = 21. Therefore, the value of each clock corresponds to the hand.
As for the bulbs, there are 5 light rays protruding from each bulb. Each light ray is thus worth 3, according to the equation.
Therefore, the last equation can be deduced.
9+9x(12x3)
= 333
