1+1=3
a+b=c
(3a-2a)+(3b-2b) = (3c-2c)
3a+3b-2a-2b = 3c-2c
2c-2a-2b = 3c-3a-3b
(1+1)c-(1+1)a-(1+1)b=3(c-a-b)
(1+1)(c-a-b)=3(c-a-b)
(1+1)=3
thoughts?
a+b=c
(3a-2a)+(3b-2b) = (3c-2c)
3a+3b-2a-2b = 3c-2c
2c-2a-2b = 3c-3a-3b
(1+1)c-(1+1)a-(1+1)b=3(c-a-b)
(1+1)(c-a-b)=3(c-a-b)
(1+1)=3
thoughts?
