>>11663352The location of a particle in our conventional four-dimensional time-space fabric can be described with (x,y,z,t) where (x,y,z) is the space-vector and t the time. Conventionally, the space vector depends on t, so we actually have (x(t),y(t),z(t),t).
Because of general relativity, the displacement rate of (x,y,z) influences t, therefore t depends on a function g(x',y',z'). We then get (x(t),y(t),z(t),t(g(x',y',z')). But t of the particle is not identical with t of the inertial point we chose so we get: (X(T),Y(T),Z(T),T(g(x'(t),y'(t),z'(t))) where T is the time how it is experienced by the particle and t the time of the referential point, with a clearly established relation between X(T) and x'(t) that everyone can look up in any book on relativity.
>>11663383consider (X(T),Y(T),Z(T),T(g(x'(t),y'(t),z'(t)))
reduce number of spatial dimensions and increase number of temporal dimensions, you get: (X(T1,T2,T3),T1(g(x'(t1,t2,t3))),T2(g(x'...)
Rewrite X as T and T1,T2,T3 as X,Y,Z and you get (T(X,Y,Z),X(g(t'(x,y,z))),Y(g(t'(x,y,z)),Z(g(t'(x,y,z))))
and compare it with (X(T),Y(T),Z(T),T(g(x'(t),y'(t),z'(t))).
Now they're both equal when T = g(T'(x,y,z)), and (X,Y,Z) = g(x'(t),y'(t),z'(t)). The math is ultimately more complicated but that is a known hypothetical property of tachyons.
