>>11632674the long way? there are 2 diodes. simplified each is either conducting or not. so there are 4 cases. calculate each one.
if assuming a non-conducting state just cut open the circuit. for a conducting (ideal) diode replace it with a short circuit(wire). then calculate the currents where the diodes have been. if you get a negative current for a conducting diode or a positive voltage for a non-conducting, disregard this case and switch to the next one.
pretty tedious but so is life. more accurate would be not assuming an ideal diode and replacing the presumed conducting diode with a 0.6V(silicium) or 0.3V(schottky) voltage drop(voltage source) instead of the short circuit.
