/sci/ - Science & Math » Thread #11612950

48KiB, 977x400, Math.png

View Same Google iqdb SauceNAO

Geometry

Anonymous Tue 28 Apr 17:24:42 2020 No.11612950 View Reply Original Report

Quoted By: >>11612970 >>11613455 >>11613468 >>11613702

Most dificult geometry problem. Do with your own warning.

Anonymous

Anonymous Tue 28 Apr 2020 17:32:40 No.11612970 Report

Quoted By: >>11613455

>>11612950
Whatever the hell you want, you never specified what is the probability distribution of the choice

Anonymous

Anonymous Tue 28 Apr 2020 18:07:37 No.11613081 Report

Quoted By:

bump

Anonymous

Anonymous Tue 28 Apr 2020 19:39:46 No.11613455 Report

Quoted By: >>11613460

>>11612970
Incredibly based.

>>11612950
Let's put A at (0, 0). Then the vertices of the big triangle are $(0, 0), (\frac{610}{57}, \frac{50 \sqrt{14}}{57}), (19, 0)$ . This has area $\frac{25 \sqrt{14}}{3}$ .

The vertices of the red triangle are $(9, 0), (\frac{275}{19}, \frac{20 \sqrt{14}}{19}), (\frac{605}{57}, \frac{44 \sqrt{14}}{57})$ . This has area $\frac{25 \sqrt{14}}{3}$ .

The probability is $\frac{72}{475}$

Anonymous

Anonymous Tue 28 Apr 2020 19:41:09 No.11613460 Report

Quoted By:

>>11613455
I mean the area of the red triangle is $\frac{24 \sqrt{14}}{19}$ .

Anonymous

Anonymous Tue 28 Apr 2020 19:42:03 No.11613468 Report

Quoted By:

>>11612950
i'd rather punch myself in the balls than suffer through this shit

Anonymous

Anonymous Tue 28 Apr 2020 20:54:36 No.11613702 Report

Quoted By:

>>11612950
(4/15)*(9/19)*(6/11)

Capcode	All Only User Posts Only Moderator Posts Only Admin Posts Only Developer Posts
Show Posts	All Only With Images Only Without Images
Deleted Posts	All Only Deleted Posts Only Non-Deleted Posts
Ghost Posts	All Only Ghost Posts Only Non-Ghost Posts
Post Type	All Only Sticky Threads Only Opening Posts Only Reply Posts
Results	All Grouped By Threads
Order	Latest Posts First Oldest Posts First

Your latest searches