>>11521497This is an elementary school level question. It can be solved using Rule of Three. If you honestly can't solve this you should leave /sci/ and reconsider your life.
NOTE: I'm going to use milliliters instead of grams because using the wrong unit triggers me otherwise.
Step by step:
1. We determine the desired levels of alcohol and water we would get by using the stronger vodka and following the proper formula.
We require 135.12 ml of alcohol to get the desired proportion of 22.80891% total alcohol content. We can use this for verification later.
2. We determine the level of alcohol we get from the bland vodka we are using.
We get 126.68 ml of alcohol by using the bland vodka.
3. We apply rule of three.
If adding 337.8 ml of bland vodka, nets me 126.675 ml of alcohol, then to get 135.12 ml of alcohol we would need X ml of the bland vodka, so that:
You would need to add 360.32 ml of bland vodka to get the desired amount of alcohol. Now we need to reduce the amount of water added (the alcohol has water too) so that the proper ratio is mantained.
4. We determine the excess water we have added.
Under the old formula vodka water content was...
Thus the difference is
Our need for water is thus reduced to:
Thus the final recipe is:
360.32ml of bland vodka
232.08ml of water
