Modelling the geometric progression of infection rates using WHO data

No.11497440 ViewReplyOriginalReport
Using this data to determine the geometric progression rate:

from 1 case to 100000 in 67 days. OK k^67 = 100k.

So take logarithms.

67(ln(k)) = ln(100000) so ln(k) = ln(100000)/67 = 0.17. So that means every day there are 17% more infected.
OK does this fit with next 200,000
11 days later
e(l(200000)/78)

1.16939685909018560584
yup still 17% per day
Now 4 days later 300000

e(l(300000)/82)
1.16625672662122983721
still very near 17% extra per day
Modeled.