/sci/ - Science & Math » Thread #11488686

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Anonymous Sat 21 Mar 09:16:59 2020 No.11488686 View Reply Original Report

Quoted By: >>11488692 >>11488708 >>11488714

>6.42586 e^(0.0757682 x)
Is that good or bad? I'm not familiar with viral spreading.

Anonymous

Anonymous Sat 21 Mar 2020 09:20:25 No.11488692 Report

Quoted By:

>>11488686
$\displaystyle \\ \text{Continuous compounding} \\ \displaystyle P(t)=P_{0} \, e^{rt} \\ \text{ } P_0 \; \, \text{initial value} \\ \text{ } r \quad \text{rate of growth} \\ \text{ } t \quad \text{time} \\\\ P(t_2) = 2P_0 \Rightarrow 2P_0 = P_{0} \, e^{rt_2} \\ 2 = e^{rt_2} \\ e^{ln(2)} = e^{rt_2} \\ ln(2) = rt_2 \\ t_2 = \frac{ln(2)}{r} \approx \frac{70\%}{r\%} \\ P(t_{10}) = 10P_0 \Rightarrow 10P_0 = P_{0} \, e^{rt_{10}} \\ 10 = e^{rt_{10}} \\ e^{ln(10)} = e^{rt_{10}} \\ ln(10) = rt_{10} \\ t_{10} = \frac{ln(10)}{r} \approx \frac{230\%}{r\%} $

Anonymous

Anonymous Sat 21 Mar 2020 09:31:16 No.11488708 Report

Quoted By:

>>11488686
7.5% growth per x unit
70/7.5 = 9.3
the function will double each 9.33 *(x unit)
assuming the unit is 1 day,
the function will grow 8x per month
starting at 6.4, after 1 month it's about 50

Anonymous

Anonymous Sat 21 Mar 2020 09:41:05 No.11488714 Report

Quoted By:

>>11488686
https://www.google.com/search?q=y%3D6.42586+e%5E%280.0757682+x%29

Anonymous

Anonymous Sat 21 Mar 2020 10:06:24 No.11488761 Report

Quoted By:

Oof
Yeah so I re-did it removing some early sets where it stayed at about 100 for 10 days and uh I got 3.40139 e^(0.372454 x). So, from the first 1000, the rate of growth increases 37% more than the day before, every day, it will take 34 days to reach 350,000,000. Nice.

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