>>11470199pretty sure you apply f(z) = a z z + b z + c to each of the three terms: f(x + y) = f(x) + f(y)
to get:
a(x+y)(x+y) + b(x+y) + c = ax*x + bx + c + ay*y+by +c
to get:
axx + 2axy + ayy + bx + by + c =
axx +bx + c + ayy + by + c
cancel axx, ayy and one c to get:
2axy + bx + by = bx + by + c
cancel bx and by to get:
2axy = c
Set x = 0 to get c:
0 = c.
then:
2axy = 0
means a = 0.
So, a = 0, b = anything, c = 0.
Amirite?
