No.11464820 ViewReplyOriginalReport
EE undergrad brainlet here. I can't understand how to find the half power frequencies for this filter. It makes sense for every other passive RLC filter I've seen but this one makes no sense to me. At resonance, the inductor and capacitor act like an open circuit, impedance is infinite, and no current flows. No current means no power is dissipated. Does that mean I can't just set Vo/Vi=1/sqrt2 to find the half power frequencies?