/sci/ - Science & Math » Thread #11431854

30KiB, 400x271, IMG-20200225-WA0044~01~01.jpg

View Same Google iqdb SauceNAO

Physics

Esp Sun 01 Mar 20:02:52 2020 No.11431854 View Reply Original Report

Quoted By: >>11431878 >>11431890 >>11431907 >>11432365 >>11432379 >>11433342

I NEED HELP WITH THIS PROBLEM, I DO NOT UNDERSTAND A LOT OF ITEM.
The tension on the BC cable has a magnitude of 750N. Write the force that this cable exerts on the rigid OAB member in Cartesian components. Determine the directors angles of that force.

Anonymous

Anonymous Sun 01 Mar 2020 20:10:10 No.11431878 Report

Quoted By:

>>11431854
THIS IS /SCI/, we don't do your homework here!
Go to stack physics if you need help.

Anonymous

Anonymous Sun 01 Mar 2020 20:16:30 No.11431890 Report

Quoted By:

>>11431854
oh man this exact problem was on my last exam, what a coincidence.

Anonymous

View Same Google iqdb SauceNAO angiewolf.jpg, 93KiB, 700x700

Anonymous Sun 01 Mar 2020 20:21:46 No.11431902 Report

Quoted By: >>11431905

Cable is parallel to the vector $\mathbf{u}=-1.6\mathbf{i}+0.7\mathbf{j}+(1.2-0.8)\mathbf{k}=-1.6\mathbf{i}+0.7\mathbf{j}+0.4\mathbf{k}$ . Now compute $\mathbf{\hat{u}}=\mathbf{u}/||\mathbf{u}||$ . The maginitude of the force is 750 N. Therefore $\mathbf{F}=750\mathbf{\hat{u}}$

Anonymous

Anonymous Sun 01 Mar 2020 20:23:05 No.11431905 Report

Quoted By:

>>11431902
Whoops, I didn't see the angle in the pipe. Doesn't matter, it's the exact same procedure. Figure it out, OP.

Anonymous

Anonymous Sun 01 Mar 2020 20:23:50 No.11431907 Report

Quoted By:

>>11431854
Start by deciding the coordinate of point B.

Anonymous

View Same Google iqdb SauceNAO angiewolf.jpg, 93KiB, 700x700

Anonymous Sun 01 Mar 2020 20:32:06 No.11431931 Report

Quoted By: >>11432361

Cable is parallel to the vector $\mathbf{u}=-1.6\mathbf{\hat i}+(0.7+0.8\sin 30^\circ)\mathbf{\hat j}+(1.2-0.8\cos 30^\circ)\mathbf{\hat k}$ . Now compute $\mathbf{\hat{u}}=\mathbf{u}/||\mathbf{u}||$ . The maginitude of the force is 750 N. Therefore $\mathbf{F}=750\mathbf{\hat{u}}$ . The directions of the force are then $\theta_i=\arccos(\mathbf{\hat u}\cdot\mathbf{\hat e}_i)$ where e_i is each basis vector and theta_i is the angle between u hat and the relevant basis element.

Anonymous

Anonymous Sun 01 Mar 2020 22:53:28 No.11432361 Report

Quoted By: >>11432372 >>11432374 >>11433287

>>11431931
I'm a freshman in college for engineering is this shit really as hard as it looks?

Anonymous

Anonymous Sun 01 Mar 2020 22:55:10 No.11432365 Report

Quoted By:

>>11431854
God I hate statics. The most tedious shit I can think of.

Anonymous

Anonymous Sun 01 Mar 2020 22:56:19 No.11432372 Report

Quoted By: >>11432376

>>11432361
It looks pretty easy to me.

Anonymous

Anonymous Sun 01 Mar 2020 22:57:11 No.11432374 Report

Quoted By: >>11432376

>>11432361
It's not hard at all

Anonymous

Anonymous Sun 01 Mar 2020 22:58:11 No.11432376 Report

Quoted By: >>11432381 >>11433287

>>11432372
>>11432374
don't lie to me

Anonymous

Anonymous Sun 01 Mar 2020 22:59:15 No.11432379 Report

Quoted By:

>>11431854
Like all statics problems, you start by drawing a million right-angled triangles. Keep drawing triangles until the problem is solved

Anonymous

View Same Google iqdb SauceNAO 1575071292986.jpg, 92KiB, 1000x1023

Anonymous Sun 01 Mar 2020 23:00:06 No.11432381 Report

Quoted By: >>11432384

>>11432376
Statics is very easy. Literally two equations the whole semester. You might just be lazy. It will only get harder.

Anonymous

Anonymous Sun 01 Mar 2020 23:01:41 No.11432384 Report

Quoted By: >>11432394 >>11433287

>>11432381
I'm doing good right now I have a 3.5 in second semester, I was just wondering so I know what I am getting myself into.

Anonymous

Anonymous Sun 01 Mar 2020 23:03:47 No.11432394 Report

Quoted By: >>11432396

>>11432384
Im being very honest when I tell you that statics should be easy (even if it is boring and tedious).

Anonymous

Anonymous Sun 01 Mar 2020 23:04:31 No.11432396 Report

Quoted By: >>11433199

>>11432394
If it's not to much harder than Chemistry i should be fine.

Anonymous

Anonymous Mon 02 Mar 2020 05:22:59 No.11433199 Report

Quoted By:

>>11432396
wait until you get to tensors and literally anything dynamics

Anonymous

Anonymous Mon 02 Mar 2020 06:09:05 No.11433287 Report

Quoted By:

>>11432361
>>11432376
>>11432384
Statics is High School Geometry meets 3D Coordinate Systems.

Anonymous

Anonymous Mon 02 Mar 2020 06:39:03 No.11433333 Report

Quoted By:

Isn’t this just Newton’s third lmao

Anonymous

Anonymous Mon 02 Mar 2020 06:43:39 No.11433342 Report

Quoted By:

>>11431854
This is like second week of a basic statics course OP, get it together and break everything down into it's respective vector component and sum all forces and moments equal to zero.

Capcode	All Only User Posts Only Moderator Posts Only Admin Posts Only Developer Posts
Show Posts	All Only With Images Only Without Images
Deleted Posts	All Only Deleted Posts Only Non-Deleted Posts
Ghost Posts	All Only Ghost Posts Only Non-Ghost Posts
Post Type	All Only Sticky Threads Only Opening Posts Only Reply Posts
Results	All Grouped By Threads
Order	Latest Posts First Oldest Posts First

Your latest searches