>>11328019So assuming 24 posts, 8/9 chance of nothing, 0.1 chance of dubs, 0.01 chance of trips, and 0.0001 chance of quads, and each being mutually exclusive, we get that 0.1^9*0.01^4*0.001*(8/9)^10 = 3*10^-22 odds for this combination compared to any other possible quantities of gets.
Naturally numbers increase at a constant rate so it's not entirely random.
