>>11256872sure if x and y represent the hour and minute hand respectively we think of them as points on the unit circle so that for t in [0,12)
x = e^(2? t i / 12) and y = e^(2? t i)
the condition that the hour and minute hands are opposite one another is simply x = - y : which is equivalent to:
e^(2? t i) = - e^(2? t i / 12)
which gives after simplifying
e^(11? t i / 6) = -1
