Quoted By:
248+208 =
200+40+8+200+8 =
10(20+20+4)+2(8) =
(5+5)(20+20+4)+(1+1)(4+4) =
(5+5)(4)(5+5+1)+(1+1)(2)(2+2) =
5(1+1)(2+2)(5+5+1)+(1+1)(1+1)2(1+1) = 5(1+1)2(1+1)(5+5+1)+(1+1)(1+1)(1+1)(1+1) = 5(1+1)(1+1)(1+1)(5(1+1)+1)+(1+1)(1+1)(1+1)(1+1)
>Let x = 1+1
5(x)(x)(x)(5(x)+1)+(x)(x)(x)(x) =
5x^3(5x+1)+x^4 =
25x^4+5x^3+x^4 =
26x^4+5x^3 =
x^3(26x+5)
>Now to solve for (1+1)
1+1 =
.999+.999 =
3(1/3)+3(1/3) =
(1/3)(3+3) =
(.333)(3)(1+1) =
(.333)(3)(x) =
(.333)(1+1+1)(x) =
(.333)(x+1)(x) =
(.333)(x^2+x) = x
(.333)(x^2+x) - x = 0
>Solving the above quadratic equation gives us the values (0,2) for x, due to 2 being (1+1), creating an endless loop, we go with 0.
x = 0
x^3(26x+5) = 0*0+5 = 5
Therefore,
248+208 = 5
