/sci/ - Science & Math » Thread #11218537

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Anonymous Wed 11 Dec 23:50:43 2019 No.11218537 View Reply Original Report

Quoted By: >>11218545 >>11218548 >>11218556 >>11218812 >>11218886 >>11220042 >>11222005

Why is x a subset of A = {x,{x,y,z},{x,z}}?

Anonymous

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Anonymous Wed 11 Dec 2019 23:53:42 No.11218545 Report

Quoted By:

>>11218537
>Why is x a subset of A = {x,{x,y,z},{x,z}}?

Anonymous

Anonymous Wed 11 Dec 2019 23:55:12 No.11218548 Report

Quoted By: >>11218556 >>11218886

>>11218537
x is not necessarily a set, nor is it a subset of {x, {x,y,z}, {x, z}} even if it is.

Anonymous

Anonymous Wed 11 Dec 2019 23:58:42 No.11218556 Report

Quoted By: >>11218573 >>11218886

>>11218537
it's not
>>11218548
>x is not necessarily a set
in set theory it is

Anonymous

Anonymous Thu 12 Dec 2019 00:08:02 No.11218573 Report

Quoted By: >>11218886

>>11218556
x != {x} is the point I think they were trying to makez

Anonymous

Anonymous Thu 12 Dec 2019 00:38:13 No.11218654 Report

Quoted By: >>11218752

huh x is a subset of A.

x \in {x,{x,y,z,],{x,z}}

Anonymous

Anonymous Thu 12 Dec 2019 01:05:46 No.11218752 Report

Quoted By: >>11218886

>>11218654
Nah, x is a member

Anonymous

Anonymous Thu 12 Dec 2019 01:27:04 No.11218812 Report

Quoted By: >>11218886

>>11218537
Should be {x}

Anonymous

Anonymous Thu 12 Dec 2019 01:54:30 No.11218886 Report

Quoted By: >>11218927

>>11218537
>>11218548
>>11218556
>>11218573
>>11218752
>>11218537
>>11218812
Unless we take the regularity axiom,
x could be a subset of A. There's really just not enough information to solve this problem.

Anonymous

Anonymous Thu 12 Dec 2019 02:09:11 No.11218927 Report

Quoted By: >>11218939 >>11218945

>>11218886
Of course it could be in a naive setting. But anyone posting this on /sci/ is not well versed in modern logic.

Anonymous

Anonymous Thu 12 Dec 2019 02:12:59 No.11218939 Report

Quoted By:

>>11218927
ZF isn't modern.

Anonymous

Anonymous Thu 12 Dec 2019 02:14:25 No.11218945 Report

Quoted By:

>>11218927
Not naive, just take the anti-wellfounded set theory that allows to define sets coinductively rather than inductively as through the more standard regularity axiom.

Anonymous

Anonymous Thu 12 Dec 2019 02:14:54 No.11218946 Report

Quoted By:

What are all these undefined symbols? x could be the empty set, which would make it both subset and member of A, for all I know.

Anonymous

Anonymous Thu 12 Dec 2019 02:35:15 No.11219000 Report

Quoted By:

ohh fuck i forgot subsets are actually sets. lmao. yeah {x} is a subset of A

Anonymous

Anonymous Thu 12 Dec 2019 13:46:05 No.11220042 Report

Quoted By: >>11220320 >>11222008

>>11218537
$x \in A$
$\{x\} \subset A$

Anonymous

Anonymous Thu 12 Dec 2019 15:41:38 No.11220224 Report

Quoted By:

Is matter a mathematical group?

Anonymous

Anonymous Thu 12 Dec 2019 16:32:50 No.11220320 Report

Quoted By:

>>11220042
/thread

Anonymous

Anonymous Fri 13 Dec 2019 06:10:20 No.11222005 Report

Quoted By:

>>11218537
you must have meant why x is an element of A
because by definition of A we have forall t t in A iff t = x or t = {x,y,z} or t = {x,z}
hence x in A iff x = x or x = {x,y,z} or x = {x,z}
since x = x we can conclude that x in A

Anonymous

Anonymous Fri 13 Dec 2019 06:13:58 No.11222008 Report

Quoted By:

>>11220042
Yep.

Anonymous

Anonymous Fri 13 Dec 2019 06:17:11 No.11222012 Report

Quoted By:

*sigh*
let B = {x} is B a subset of A?

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