>>11214069A=A
A+C=A+B
C may or may not be equals to B, depending on initial conditions
A-A=B-C
0=B-C
B-C=0 if B=C, B-C=D (D=/=0 if B=/=C)
Therefore, assuming B=/=C...
A=A+B-C
A-A=B-C
0=D
D cannot be zero if B=/=C by definition.
Therefore math does not exist.
