>>11201125Compare to the integral; the integral from 1 to infinity which is easily evaluated is greater than the sum from n=2 on up. So the sum is bounded from above (adding in the first term)/
As all the terms in the sum are positive, it is > 0, and also the progressive sums are monotone increasing it converges.
Also I know what this is about and I am reporting your ass. Consider yourself busted.
