/sci/ - Science & Math » Thread #11159278

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You should be able to solve this

Anonymous Tue 19 Nov 03:47:07 2019 No.11159278 View Reply Original Report

Quoted By: >>11159703 >>11159707 >>11159739

Anonymous

Anonymous Tue 19 Nov 2019 04:57:58 No.11159472 Report

Quoted By: >>11159484 >>11159686

Shit like this is why we have integral approximation methods.

Anonymous

Anonymous Tue 19 Nov 2019 05:02:51 No.11159484 Report

Quoted By:

>>11159472
no it's not.

Anonymous

Anonymous Tue 19 Nov 2019 05:10:32 No.11159493 Report

Quoted By: >>11159619

>punch into wolfram alpha
jesus fuck. is there actually an efficient way to comptute this?
being good at finding arbitrary antiderivatives is a bullshit skill btw

Anonymous

Anonymous Tue 19 Nov 2019 06:07:50 No.11159619 Report

Quoted By:

>>11159493
>complex residues
>quartic equation formula

Anonymous

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Anonymous Tue 19 Nov 2019 06:11:21 No.11159625 Report

Quoted By:

Amidonitrite.

Anonymous

Anonymous Tue 19 Nov 2019 06:43:21 No.11159663 Report

Quoted By:

im stuck on an improper integral problem right now it sucks this shit is gay as fuck

Anonymous

Anonymous Tue 19 Nov 2019 06:55:29 No.11159686 Report

Quoted By:

>>11159472
https://en.wikipedia.org/wiki/Residue_theorem

Anonymous

Anonymous Tue 19 Nov 2019 07:03:09 No.11159703 Report

Quoted By:

>>11159278
If you can solve
$\beta - \frac{1}{\beta} = \alpha$
$\beta + \frac{1}{\beta} = \frac{1}{\alpha}$
Then you can solve this with partial fractions.

Anonymous

Anonymous Tue 19 Nov 2019 07:07:49 No.11159707 Report

Quoted By:

>>11159278
$\beta - \frac{1}{\beta} = {\alpha}^{2} [\eqn]<br /><script type="math/tex; mode=display"> \beta + \frac{1}{\beta} = \frac{1}{\alpha}$
Then you can use alpha and beta to get the partial fraction decomposition.

Anonymous

Anonymous Tue 19 Nov 2019 07:34:02 No.11159739 Report

Quoted By:

>>11159278
Apply quotient rule.

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