Utterly trivial.
Horizontal velocity is constant throughout an object's motion. The object is displaced 30m horizontally from launch in 2.4 seconds, giving the object a horizontal velocity of 12.5 meters per second.
Objects follow a parabolic path while in flight, assuming no air resistance, and thusly we can say the object reached it's peak height after 1.2 seconds of flight, given that the ball is in the air for 2.4 seconds. Acceleration due to gravity causes the ball to lose 9.8m/s of velocity every second, and we know at the object's peak it has no vertical velocity at all. Thus, we can say that the ball must lose 1.2 chunks of 9.8m/s of velocity, therefore giving us 11.76m/s for the ball's initial vertical velocity.
The ball's overall velocity is the square root of the sum of its component squres, therefore we have sqrt(11.76^2 + 12.5^2) = 17.16m/s for the initial velocity.
The angle of launch is the arctangent of the two components, thus arctan(11.76/12.5) = 43.25 degrees.
Solve 9 by yourself you dumb swine.
