/sci/ - Science & Math » Thread #11098641

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Anonymous Mon 28 Oct 11:19:06 2019 No.11098641 View Reply Original Report

Quoted By: >>11098643 >>11098644 >>11098659 >>11098664 >>11098782

Hi /sci/
I forgot how to do this when you use y
pls help
ty

Anonymous

Anonymous Mon 28 Oct 2019 11:20:36 No.11098643 Report

Quoted By:

>>11098641
You have to be 18+ to post here

Anonymous

Anonymous Mon 28 Oct 2019 11:21:23 No.11098644 Report

Quoted By: >>11098659

>>11098641
just divide by y^2 and multiply by dx man

Anonymous

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Anonymous Mon 28 Oct 2019 11:34:24 No.11098659 Report

Quoted By: >>11098664 >>11098690

>>11098641
hello /pol/ here

do what this gentleman said >>11098644
here's an illustration. You can do the rest

Anonymous

Anonymous Mon 28 Oct 2019 11:35:12 No.11098661 Report

Quoted By:

Choose a value for x. Lets assume it's 1.
X = 1
Y(1) = 1
Y = 1

DY/DX = 1^2
D(1)/D(1) = 1^2
D/D = 1
1 = 1

Simple stuff, you can always make an X Y table if you can't figure it out. Let me know if you need any more help

Anonymous

Anonymous Mon 28 Oct 2019 11:36:18 No.11098664 Report

Quoted By:

>>11098641
>>11098659
uh let me add
you'll end up with a constant left over when you integrate. That's what the initial condition y(x=0) = 1 is for
best of luck

Anonymous

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Anonymous Mon 28 Oct 2019 11:51:55 No.11098690 Report

Quoted By: >>11098691

>>11098659
Yea. I got up to your stage in this, what I am supposed to do is to actually get Y out of the integral

Here is a picture of what I learned in uni, I'm looking over my notes now, I'm fine for most integral/diff stuff but this has confused me and my notes aren't helping.

Anonymous

Anonymous Mon 28 Oct 2019 11:53:06 No.11098691 Report

Quoted By: >>11098697

>>11098690
sorry if you dont understand my hand writing, I will make a transcript of it if required

btw, this isnt related to the question I had, just an example I learned in class.

Anonymous

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Anonymous Mon 28 Oct 2019 11:59:35 No.11098697 Report

Quoted By: >>11098701 >>11098786

>>11098691
I can read it. Kinda confused though. It looks like you have everything you need to solve the problem right there.
But here it is

Anonymous

Anonymous Mon 28 Oct 2019 12:00:37 No.11098701 Report

Quoted By:

>>11098697
oops, 1/y = 1 - 2x
y = 1/(1 - 2x)

Anonymous

Anonymous Mon 28 Oct 2019 13:01:58 No.11098782 Report

Quoted By:

>>11098641
Just watch Khan academy, bro

Anonymous

Anonymous Mon 28 Oct 2019 13:04:40 No.11098786 Report

Quoted By:

>>11098697
Integral of y^(-2) dy is -y^(-1) + C

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