>>11048095I came up with my initial answer the same way as you.
but I guess you can get to pacman facing right by noticing that the top two rows have all directions: R D D L D U.
the bottom two rows have L D U L L, so the ? must be the missing direction R.
(R = right, L = left, U = up, D = down facing pacman)
another way is to count how many clockwise quarter (90 deg) rotations each one is from the one next to it.
assume numbering like so:
1 2 3
4 5 6
7 8 9
then from 1->2 gives 1 quarter rotation.
2->3 gives 0 quarter rotations.
3->4 gives 1 quarter rotation.
then going 1->2->...->8->9->1 gives: 1 0 1 3 2 3 0 ? ?, or:
1 0 1
3 2 3
0 ? ?
then the 2nd ? must be a 0 like so:
1 0 1
3 2 3
0 ? 0
and as 9->1 = 0 quarter rotations, they must be the same.
so it must be the right-facing pacman.
