>sqrt(i) = x = ((-1)^(1/2))^(1/2)
>x = -1^(1/4)
>x^8 = -1^2 = 1
>x = 1^(1/8) = +/- 1
>sqrt(i) = -1 or 1
where to collect my fields medal faggots?
>x = -1^(1/4)
>x^8 = -1^2 = 1
>x = 1^(1/8) = +/- 1
>sqrt(i) = -1 or 1
where to collect my fields medal faggots?
