/sci/ - Science & Math » Thread #10976121

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Anonymous Sun 15 Sep 20:50:44 2019 No.10976121 View Reply Original Report

Quoted By: >>10976188 >>10976222 >>10976233 >>10976235 >>10976277

If you can express the length d in terms of just the lengths a and b, with no mention of the length c, then you are in the top half of /sci/ posters.

Anonymous

Anonymous Sun 15 Sep 2019 21:11:44 No.10976188 Report

Quoted By: >>10976198

>>10976121
you can do this with b/a i believe

Anonymous

Anonymous Sun 15 Sep 2019 21:15:55 No.10976197 Report

Quoted By:

Well, there are some ways. Using the total area, just maintaning the radiciation of axa+bxb...

Anonymous

Anonymous Sun 15 Sep 2019 21:16:21 No.10976198 Report

Quoted By:

>>10976188
lol wrong

Anonymous

Anonymous Sun 15 Sep 2019 21:18:55 No.10976203 Report

Quoted By:

2xArea/radiciation of axa+bxb=d

Anonymous

Anonymous Sun 15 Sep 2019 21:19:28 No.10976206 Report

Quoted By: >>10976228

$a=3$
$b=4$
$c=5$
$d={12}/{5}$

Anonymous

Anonymous Sun 15 Sep 2019 21:23:42 No.10976222 Report

Quoted By:

>>10976121
ab/sqrt(a^2+b^2)

Anonymous

Anonymous Sun 15 Sep 2019 21:25:54 No.10976228 Report

Quoted By:

>>10976206
>with no mention of length c

Anonymous

Anonymous Sun 15 Sep 2019 21:28:49 No.10976233 Report

Quoted By:

>>10976121
a*sin(arctan(b/a))

Anonymous

Anonymous Sun 15 Sep 2019 21:29:55 No.10976235 Report

Quoted By:

>>10976121
dc/2 = ab/2
dc = ab
d = ab/c
d = ab/sqrt(a^2 + b^2)

Anonymous

Anonymous Sun 15 Sep 2019 21:48:42 No.10976277 Report

Quoted By:

>>10976121
trigonometry

Anonymous

Anonymous Sun 15 Sep 2019 21:50:49 No.10976280 Report

Quoted By: >>10976297

Isn't it some shit like 1/d^2 = 1/a^2 + 1/b^2?

Anonymous

Anonymous Sun 15 Sep 2019 22:01:13 No.10976297 Report

Quoted By: >>10976322

>>10976280
Hi Greg

Anonymous

Anonymous Sun 15 Sep 2019 22:13:15 No.10976322 Report

Quoted By: >>10976544 >>10976558

>>10976297
Do you mean Greg Egan?

Anonymous

Anonymous Sun 15 Sep 2019 23:55:44 No.10976544 Report

Quoted By:

>>10976322
no

Anonymous

Anonymous Mon 16 Sep 2019 00:02:21 No.10976558 Report

Quoted By: >>10976583

>>10976322
I mean Greg anal anal implant rape machine.

Anonymous

Anonymous Mon 16 Sep 2019 00:10:23 No.10976583 Report

Quoted By:

>>10976558
I think you mean J-Tookz

Anonymous

Anonymous Mon 16 Sep 2019 00:27:00 No.10976635 Report

Quoted By: >>10976648

$d=\frac{a·b}{\sqrt{a^2+b^2}}$

Anonymous

Anonymous Mon 16 Sep 2019 00:30:57 No.10976648 Report

Quoted By:

>>10976635
$d=\frac{a·b}{\sqrt{a^{2}+b^{2}}}$

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