/sci/ - Science & Math » Thread #10959418

680KiB, 1000x1024, solve.png

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Anonymous Mon 09 Sep 19:27:46 2019 No.10959418 View Reply Original Report

Quoted By: >>10959427 >>10959539 >>10959571 >>10959616 >>10959655

Well? Can you?

Anonymous

Anonymous Mon 09 Sep 2019 19:30:54 No.10959427 Report

Quoted By:

>>10959418
no. image is shit. does that volume start at the edge of the black or the purple, what about the volume of the sphere, does the diameter only include the red line or to the edge of the... Is that supposed to be a circle or a pixelated mess of garbage.

Anonymous

Anonymous Mon 09 Sep 2019 20:26:51 No.10959539 Report

Quoted By:

>>10959418
200

Anonymous

Anonymous Mon 09 Sep 2019 20:36:10 No.10959571 Report

Quoted By:

>>10959418
Of course: d = X
Where do I get a Fields medal?

Anonymous

Anonymous Mon 09 Sep 2019 20:54:30 No.10959616 Report

Quoted By: >>10959669

>>10959418
So is the volume of the ENTIRE sphere 100 or just the spherical cap. If 100 is the entire volume its trivial ofc, but if 100 is the volume of the spherical cap we must either know the height of the cap or the radius of the basis of the cap to get the radius and thus the diameter out of this.

Anonymous

Anonymous Mon 09 Sep 2019 21:08:57 No.10959655 Report

Quoted By: >>10959660 >>10959669

>>10959418
No solution exists.

Proof.
Take V(h,R) to be evolution of water of hight h poured into a spherical container of radius R.

The problem gives V(h,R) = 100. But for every R, I can choose a hight h (0 < h < 2R), such that the volume is 100.

Anonymous

Anonymous Mon 09 Sep 2019 21:10:17 No.10959660 Report

Quoted By:

>>10959655
> Take V(h,R) to be evolution of water
I meant volume. I type one letter off, and my browser guesses something completely left field.

Anonymous

Anonymous Mon 09 Sep 2019 21:12:25 No.10959669 Report

Quoted By:

>>10959655
Exaclty! As I stated in >>10959616 already, there must be given a height OR the radius of the base of the spherical cap that works aswell. because that would be equal to sqrt((2*r - h)*h).

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