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Pre-cal 11 factoring help

Anonymous Mon 09 Sep 01:57:32 2019 No.10957612 View Reply Original Report

Quoted By: >>10957626

Hello, I've been struggling to factor and I need help with this specific equation:

275n^3 + 1210n^2 + 1331n

anyone could help me?

Anonymous

Anonymous Mon 09 Sep 2019 01:58:55 No.10957618 Report

Quoted By:

first
n(275*n^2+10*n+1331)
then use the quadratic formula

Anonymous

Anonymous Mon 09 Sep 2019 02:00:34 No.10957626 Report

Quoted By:

>>10957612
>anyone could help me?
What have you tried?

Anonymous

Anonymous Mon 09 Sep 2019 02:05:15 No.10957639 Report

Quoted By: >>10957767

I have tried doing GCF method, so I divided 275, 1210, and 1331 all by 11 - because that is their greatest common factor. after that i got:

25n^3 + 110n^2 + 121n

after that I am suppose to find a number that multiples to 121, but adds to 110? I feel like i am missing a step

Anonymous

Anonymous Mon 09 Sep 2019 02:11:51 No.10957653 Report

Quoted By:

And if anyone is wondering, the answer is:

11n(5n+11)(5n+11), but I don't know how they got that without using the quadratic formula

Anonymous

Anonymous Mon 09 Sep 2019 03:04:13 No.10957767 Report

Quoted By:

>>10957639
25 is only divisible by the pairs 1,25 and 5,5
121 is only divisible by the pairs 1,121, and 11,11
because 1,25 and 1,121 clearly won't work in this case, the only remaining whole number possibility is (5x+11)(5x+11) or (5x+11)^2

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