/sci/ - Science & Math » Thread #10876435

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Anonymous Fri 09 Aug 22:12:32 2019 No.10876435 View Reply Original Report

Quoted By:

Show your work guys! Not my homework!

Anonymous

Anonymous Fri 09 Aug 2019 22:19:45 No.10876457 Report

Quoted By: >>10876505 >>10876510 >>10876564 >>10876699

lol how can you even integrate to “2/i”? Also what the fuck is the “s” for it’s not even in the expression kek schizo come back with some real math I ain’t falling for this bait

Anonymous

Anonymous Fri 09 Aug 2019 22:40:49 No.10876505 Report

Quoted By: >>10876598

>>10876457
This integral is on a complex domain that's how you can integrate from 0 to 2/I.
Also some if you take $\mathcal{L}\{y(t)\}=Y(s)$ you get a function of s hence why you need the ds.

Anonymous

Anonymous Fri 09 Aug 2019 22:42:46 No.10876510 Report

Quoted By: >>10876514

>>10876457
>integrate to 2/i
perfectly acceptable
>what the fuck is the “s” for it’s not even in the expression
He's got you there, op.
>heh, the Laplace transform requires you to change the variable from 't' to 's'
brainlet. It's obvious this isn't your homework because something this idiotic would never be assigned.

Anonymous

Anonymous Fri 09 Aug 2019 22:44:25 No.10876514 Report

Quoted By: >>10876528

>>10876510
>brainlet. It's obvious this isn't your homework because something this idiotic would never be assigned.
Solve it then if it's so idiotic. The solution is nice.

Anonymous

Anonymous Fri 09 Aug 2019 22:51:13 No.10876528 Report

Quoted By: >>10876531 >>10876553 >>10876564 >>10876753

>>10876514
solution:-(2/i)L{-cosh(-t)sinh(t)}

Anonymous

Anonymous Fri 09 Aug 2019 22:52:30 No.10876531 Report

Quoted By: >>10876539 >>10876553

>>10876528
Nay, do the transform first then integrate the solution if the transform.

Anonymous

Anonymous Fri 09 Aug 2019 22:54:58 No.10876539 Report

Quoted By:

>>10876531
>do the transform first then integrate the solution if the transform
>the laplace transform requires an input in the variable t and an output in the variable s
brainlet

Anonymous

Anonymous Fri 09 Aug 2019 22:59:56 No.10876553 Report

Quoted By: >>10876555 >>10876564

>>10876528
>>10876531
final answer 2i/(x^2-16). Op you fucked up again.

Anonymous

Anonymous Fri 09 Aug 2019 23:00:26 No.10876555 Report

Quoted By: >>10876559

>>10876553
Nope

Anonymous

Anonymous Fri 09 Aug 2019 23:01:15 No.10876556 Report

Quoted By: >>10876564

The answer is 0

Anonymous

Anonymous Fri 09 Aug 2019 23:02:42 No.10876559 Report

Quoted By: >>10876578

>>10876555
fuck off there's nothing in the OP that says I have to transform first and use the exact same dummy variables you use. How about asking the question properly first.

Anonymous

Anonymous Fri 09 Aug 2019 23:03:57 No.10876564 Report

Quoted By:

>>10876457
>>10876528
>>10876553
>>10876556
All correct answers.

Anonymous

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Anonymous Fri 09 Aug 2019 23:07:39 No.10876570 Report

Quoted By: >>10876577

1/2 * (-ln|2| -1/2 * pi * i * k * 2pi) $k \in (\mathbb{N} \cup 0),$
Is what I got with some sloppy calculations , so it is probably wrong but it is midnight here.

Anonymous

Anonymous Fri 09 Aug 2019 23:10:38 No.10876577 Report

Quoted By:

>>10876570
Just redid the steps and I messed up in my setup brb remaking solution

Anonymous

Anonymous Fri 09 Aug 2019 23:11:04 No.10876578 Report

Quoted By: >>10876587

>>10876559
Okay here's the steps (idk why this isn't obvious kek) here's me spoon feeding you.

1. Compute the transform
2. integrate the result of the transform wrt s

Anonymous

Anonymous Fri 09 Aug 2019 23:15:53 No.10876587 Report

Quoted By: >>10876598

>>10876578
That's literally what I did. How do you know that the variable I get out of the transformation will be 's'? You don't. It's a dummy variable. It could be any variable I decide, such as x, making the problem much simpler. And if a professor at my #5 math school in the country tried to pull this shit on me, I would take it straight to the department head.

Anonymous

Anonymous Fri 09 Aug 2019 23:19:01 No.10876598 Report

Quoted By: >>10876602 >>10876715

>>10876587
okay then use the transform of the variable I used in >>10876505 to go from s to t. Idk why you refuse to atleast try this?

Anonymous

Anonymous Fri 09 Aug 2019 23:20:15 No.10876601 Report

Quoted By:

1+1 = 3

Anonymous

Anonymous Fri 09 Aug 2019 23:20:34 No.10876602 Report

Quoted By:

>>10876598
I meant t to s*

Anonymous

Anonymous Fri 09 Aug 2019 23:25:55 No.10876616 Report

Quoted By: >>10876619

1/8 * ln(2) ??????

Anonymous

Anonymous Fri 09 Aug 2019 23:27:55 No.10876619 Report

Quoted By: >>10876636

>>10876616
Close!

Anonymous

Anonymous Fri 09 Aug 2019 23:32:29 No.10876636 Report

Quoted By: >>10876639 >>10876644 >>10876649

>>10876619
Yeah I messed up again by reading a one as an i
but my final answer is: -1/4 * ln(i)

ln(i) = (1/2 + k*2) * pi *i where k is any natural number

thus -1/4 * (1/2 + k*2) * pi *i is a solution for any k

Anonymous

Anonymous Fri 09 Aug 2019 23:33:32 No.10876639 Report

Quoted By: >>10876649

>>10876636
and fuck me if this is wrong

Anonymous

Anonymous Fri 09 Aug 2019 23:34:27 No.10876644 Report

Quoted By: >>10876647 >>10876655

>>10876636
Ooooooooo so close!

Anonymous

Anonymous Fri 09 Aug 2019 23:34:54 No.10876647 Report

Quoted By:

>>10876644
1/4 * ln(i)

Anonymous

Anonymous Fri 09 Aug 2019 23:35:33 No.10876649 Report

Quoted By:

>>10876636
>>10876639
Fuck man atleast you're trying I can give you that man.

Anonymous

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Anonymous Fri 09 Aug 2019 23:37:50 No.10876655 Report

Quoted By:

>>10876644
-1/4* ln(-i)
I am going to bed now sleep tight anons

Anonymous

Anonymous Fri 09 Aug 2019 23:53:45 No.10876699 Report

Quoted By:

>>10876457
I'm not sure if low quality bait or brainlet.

Anonymous

Anonymous Fri 09 Aug 2019 23:54:46 No.10876704 Report

Quoted By:

ITT: what are branch cuts

Anonymous

Anonymous Fri 09 Aug 2019 23:58:15 No.10876715 Report

Quoted By: >>10876723

>>10876598
Because there are various many branches of math, and not all of them have to do with
>muh hard integrals
Some of them have more to do with actually defining the question you want answered properly. That's what I'm in to, so that's why I refuse to solve until you ask properly.

Anonymous

Anonymous Sat 10 Aug 2019 00:00:49 No.10876723 Report

Quoted By: >>10876753

>>10876715
Doesn't matter this guy is very close to getting it >10876647

Anonymous

Anonymous Sat 10 Aug 2019 00:14:39 No.10876753 Report

Quoted By:

>>10876723
getting what? my answer>>10876528
is perfectly correct.

Anonymous

Anonymous Sat 10 Aug 2019 00:17:46 No.10876763 Report

Quoted By:

I wonder how op feels that this guy is following him around trolling all his threads.

Anonymous

Anonymous Sat 10 Aug 2019 00:33:14 No.10876797 Report

Quoted By:

$\int_{0}^{-2i} L{\cdots}ds = -2 \pi \frac{1}{4} n i$ n being an integer depending on the branch cut you choose...in other words how you define Log(z).

Anonymous

Anonymous Sat 10 Aug 2019 00:34:17 No.10876798 Report

Quoted By:

$-\frac{\pi}{2}in$

Anonymous

Anonymous Sat 10 Aug 2019 01:39:15 No.10876917 Report

Quoted By:

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