>>10860463what's so hard about it? There's not even the need to use any tricks.
at 0+, -1/x tends towards - infinity and 2^(-1/x) goes towards 0. The denominator goes to 1. So the first limit is 1
at 0-, -1/x tends towards + infinity, and 2^(-1/x) goes towards + infinity. The denominator goes to infinity. So the second limit is 0.
