>>10842009I'll give you the solution soon, but here is a real way of doing it, since we are working in C, let z = x + iy, u1 = a + ib, u2 = c + id, u3 = e + if, r1 = k, r2 = l, r3 = m. Then the system of equations to solve is,
|z - u1| = r1
|z - u2| = r2
|z - u3| = r3
Expand the first one by squaring both sides and using the |z|^2 = z * conj(z) identity, then expand, you will have 3 linear equations in |z|^2, z and conj(z).
