>>10852334>>10852332>Look at me guys! I can copy text from stackexchange!MUHAMMAD FUCKING CHRIST LET ME JUST TYPE IT OUT FOR YOU STUPID MOUTH BREATHING WHORESONS
IT IS ASSUMED (BY THE QUESTION NOT BY ME) THAT
IF HAS A DISCONTINUITY THEN BECAUSE IS DIFFERENTIABLE IT HAS TO BE A NON-EXISTENCE AND NOT A JUMP CONTINUITY, FOR EXAMPLE CONSIDER SINGULARITY DISCONTINUITIES AT 0 AND 1, IF THEN SINCE IS CONTINUOUS THE NOMINATOR WILL DOMINATE SO THE ONLY POSSIBILITY IS , SIMILARLY AT THE DENOMINATOR THE ONLY POSSIBILITY IS
HOWEVER, AND THIS IS THE IMPORTANT PART, YOU SEWERRAT RAPING HARPY SPAWN. SINCE THERE HAS TO BE A (AT LEAST CONTINUOUS IF NOT DIFFERENTIABLE) SUBDOMAIN IN THE DOMAIN WHERE EXIST AND IS CONTINUOUS (AGAIN BECAUSE THERE ARE NO JUMP DISCONTINUITIES) WHEREIN THE THEOREM CAN BE APPLIED.
COOL.
THEREFORE WE ONLY CARE ABOUT THE PARTS WHERE THE FUNCTION IS CONTINUOUS IN THE DOMAIN, IT DOES NOT HAVE TO BE CONTINUOUS ACROSS THE WHOLE DOMAIN of c, BUT ANY SUBDOMAIN WILL DO. IN FACT YOU SYPHILIS INFECTED, YELLOW TEETH, FETAL ALCOHOL SYNDROME CUNTS MADE ME DOUBT MYSELF ENOUGH TO CHECK, BUT EVEN THE FUCKING WIKIPEDIA PAGE (WHICH DOES NOT CONTAIN THE MOST GENERALISED THEOREM) CONFIRMS THIS, READ HERE THE LIMITS CAN EQUAL INFINITY OR MINUS INFINITY:
https://en.wikipedia.org/wiki/Mean_value_theorem#Formal_statementFUCK.
YOU DON'T NEED TO SPELL ANY OF THIS OUT IN A PROOF BECAUSE IT IS A KNOWN FUCKING PROPERTY OF DIFFERENTIABLE FUNCTIONS. NOW YOU CAN HAVE SUPER ELEGANT AND BEAUTIFUL FUCKING PROOF USING THE THEOREMS BECAUSE THE COMPACT DOMAIN IS 1 SO THE FRACTIONS ARE EVEN EASIER TO WORK WITH. IT CAN LITERALLY BE DONE IN 3 LINES, JUST LIKE ALL THE OTHER QUESTIONS.
