>>14400708Your question makes little sense.
time out of storm = distance out of storm / speed out of storm
time in storm = distance in storm / speed in storm
total time = time out of storm + time in storm
total distance = distance out of storm + distance in storm
I assume your problem is a straight line at only two speeds and can be modeled by the above 4 equations. You additionally claim to know:
* total distance
* distance in storm
* speed in storm * resistance coefficient = speed out of storm
And you want to know:
* time in storm
I try:
time in storm = distance in storm / speed in storm
time in storm = distance in storm * resistance coefficient / speed out of storm
time out of storm = distance out of storm / speed out of storm
time out of storm = (total distance - distance in storm) / speed out of storm
total time = (1 / speed out of storm) * (distance in storm * (resistance coefficient - 1) + total distance)
fraction of time in storm = distance in storm * resistance coefficient / (distance in storm * (resistance coefficient - 1) + total distance)
So, for example, if:
total distance = 10 nautical miles
distance in storm = 5 nautical miles
resistance coefficient = 1.1 (10% slower in storm)
Then fraction of time in storm = 5 * 1.1 / (5 * 0.1 + 10) = 5.5 / 10.5 = 11/21 = 55/105 =~ 52.5%
CAUTION: Check carefully what "resistance coefficient" actually means in your problem else you might get it "backwards". For example:
10% slower in storm = 9.1% faster out of storm = 1.1 resistance coefficient = 0.91 speed coefficient
https://www.youtube.com/watch?v=aoXJfuPaFF8&t=11401. What is your native language?
2. What is your favorite subject of study?
