>>14236501Not that guy but:
Statistical significance would depend on the n as well, we can find the appropriate test statistic for each of the correlations in that table by applying the transformation r -> r * sqrt(N-2)/sqrt(1-r^2) = t which will be approximately distributed according to a t distribution with N-2 degrees of freedom.
For example, in terms of the income correlation at r = 0.2 and N = 58758 the p-value is very close to 0 (that sample size is huge).
On the other hand, the for negotiation success r = 0.07, N = 862, run the following in R: 1 - pt(0.07/sqrt(1-0.07^2) * sqrt(860), df = 860) ~ 0.02 which is "significant" if you mean below 0.05 (without using a false discovery correction)
