/sci/ - Science & Math » Thread #14179877

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I have solved the Continuum Hypothesis (false)

Anonymous Wed 02 Feb 23:44:45 2022 No.14179877 View Reply Original Report

Quoted By: >>14180053 >>14180060 >>14180089 >>14180685

This is the final draft. It took me about 3 months to get here, and nothing much more can be said. It's quite obvious from the start and there will be more.

Anonymous

Anonymous Wed 02 Feb 2022 23:51:06 No.14179901 Report

Quoted By: >>14179918

and why should i not consider the set Q to be equal to N? They have a one to one correspondence.

Anonymous

Anonymous Wed 02 Feb 2022 23:54:22 No.14179918 Report

Quoted By: >>14179927

>>14179901
Bijectivity can be established among these sets but the question is are the relations ascribing the numbers the same way or are they drawing the numbers in different "sizes." There are different kinds of infinities, some are smaller than others etc.

Anonymous

Anonymous Wed 02 Feb 2022 23:57:30 No.14179927 Report

Quoted By: >>14179947 >>14180092

>>14179918
I dont know what you mean, elaborate. It seems to me that bijectivity should be the rule that decides if two sets have the same cardinality. Do you disagree with this?

Anonymous

Anonymous Thu 03 Feb 2022 00:03:37 No.14179947 Report

Quoted By: >>14179957

>>14179927
That outlook is flawed from the start. if the bijectivity is the rule then the arithmetic, calculus, and subsequent mathematics would be as arbitrary as not deciding what the actual foundations of Mathematics are.

Anonymous

Anonymous Thu 03 Feb 2022 00:08:14 No.14179957 Report

Quoted By:

>>14179947
thats the point, a set is just like a pure idea. you dont really need to learn set theory to understand other math.

Anonymous

Anonymous Thu 03 Feb 2022 00:37:18 No.14180018 Report

Quoted By:

If CH is false then Hilbert's 2nd problem is solved; i.e.: the natural numbers lead to the integers by the law of contradiction - thereby avoiding incompleteness by giving to a new arithmetic based on self-consistency

Anonymous

Anonymous Thu 03 Feb 2022 00:48:27 No.14180046 Report

Quoted By:

>proof
>it just is

Okay

El Arcón

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El Arcón Thu 03 Feb 2022 00:51:26 No.14180053 Report

Quoted By:

>>14179877
In the proposition, how do you get to
aleph_0 < 2^aleph_0?

I agree that this is false and it follows my own program in real analysis as well (pic), but I don't see what program you're referring to when you use this less than relation.

El Arcón

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El Arcón Thu 03 Feb 2022 00:53:17 No.14180060 Report

Quoted By: >>14180082

>>14179877
In the proposition, how do you get to
aleph_0 < 2^aleph_0?

I agree that this is false and it follows from my own program in real analysis as well (pic). Still, I don't see what program you're referring to when you use this less than relation.

OP Thu 03 Feb 2022 01:01:22 No.14180082 Report

Quoted By: >>14180103

>>14180060
aleph 0 < Q < 2^Q

Anonymous

Anonymous Thu 03 Feb 2022 01:03:48 No.14180089 Report

Quoted By: >>14180101

>>14179877
There's a major flaw in this proof, you are assuming the existence of the ``real numbers"

El Arcón

El Arcón Thu 03 Feb 2022 01:04:35 No.14180092 Report

Quoted By:

>>14179927
>that bijectivity should be the rule that decides if two sets have the same cardinality
This is actually a highly nuanced issue. For instance, in my treatment of points in line segments and the numerical representations of those points, I think it follows that you could have bijectivity on a set of points which *might* not necessarily imply bijectivity with the points' numerical representations. This opens a door to some subtelty that requires further clarifications on whether or not bijectivity suffices to claim equal cardinality. Furthermore, my analysis focused on points and their numerical representations while only opening the door a future analysis of numbers and their geometric representations. That other case which I barely touched on in my paper may be different than the case I treated. If there is some characteristic of non-commutativity between (i) points and numerical representations, and (ii) numbers and their geometric representations, it is possible that one might confound the intuitive notion that "same cardinality" means "there exists a bijection."

Anonymous

Anonymous Thu 03 Feb 2022 01:06:08 No.14180101 Report

Quoted By:

>>14180089
There's a major flaw in your post. The fact you're an idiot.

El Arcón

El Arcón Thu 03 Feb 2022 01:06:44 No.14180103 Report

Quoted By:

>>14180082
Yeah, I don't get it. Usually, in most people's analytical programs, 2^INF=INF which would make
INF < 2^INF = INF

a false statement.

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OP Thu 03 Feb 2022 01:50:16 No.14180269 Report

Quoted By:

Here's the 2nd problem on the list. It follows from negation(CH).

OP Thu 03 Feb 2022 02:30:16 No.14180381 Report

Quoted By:

I made a blog, I will update concurrent with my solving the problems listed on wikipedia for mathematics. For the next 2 years, 2 theorem proofs a day.
https://123abcmathematics.blogspot.com/

Anonymous

Anonymous Thu 03 Feb 2022 02:40:28 No.14180399 Report

Quoted By:

there are (?6 N / ?)^2 more Q than N but that's not a different cardinal

Anonymous

Anonymous Thu 03 Feb 2022 02:46:46 No.14180409 Report

Quoted By: >>14180459 >>14180462 >>14180888

Nobody in this thread has solved shit

Anonymous

Anonymous Thu 03 Feb 2022 03:13:20 No.14180459 Report

Quoted By:

>>14180409
i've solved some shit and i'm itt

Anonymous

Anonymous Thu 03 Feb 2022 03:14:46 No.14180462 Report

Quoted By: >>14180463 >>14180490

>>14180409
I solved P=NP and refuse to tell you all the answer

Anonymous

Anonymous Thu 03 Feb 2022 03:16:11 No.14180463 Report

Quoted By:

>>14180462
you're a fag no one cares about word games

Anonymous

Anonymous Thu 03 Feb 2022 03:28:25 No.14180490 Report

Quoted By:

>>14180462
I already did. It's true only when N=1. Clay Math said the check is in the mail.

Frenanon

Frenanon Thu 03 Feb 2022 04:39:26 No.14180685 Report

Quoted By:

>>14179877
Checked.
>zezima

El Arcón

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El Arcón Thu 03 Feb 2022 06:12:49 No.14180888 Report

Quoted By:

>>14180409
>Nobody in this thread

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