>>14135384Let A be any set. We will find another set B such that B is not in A.
Let B={x in A, such that x is not an element of itself}
Assume for a contradiction that B is in A
Then B will be an element of itself if and only if it is not an element of itself, by definition of B, a contradiction.
Thus B is not an element of A.
This means that for all sets, there is at least one set that it's not contained in A, so there is no set that contains all sets
