/sci/ - Science & Math » Thread #14026384

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Anonymous Wed 29 Dec 01:32:56 2021 No.14026384 View Reply Original Report

Quoted By: >>14026413 >>14026472 >>14026586 >>14026604 >>14026627 >>14026737 >>14026830 >>14027721 >>14027755 >>14027937 >>14028155 >>14028684 >>14028697 >>14028705 >>14028781 >>14029874

Because.... uhhhhh... IT JUST DOES. TRUST SCIENCE

Anonymous

Anonymous Wed 29 Dec 2021 01:36:50 No.14026397 Report

Quoted By:

math is not science retard

Anonymous

Anonymous Wed 29 Dec 2021 01:37:07 No.14026398 Report

Quoted By: >>14026407

What would you prefer it be equal to?

Anonymous

Anonymous Wed 29 Dec 2021 01:40:16 No.14026407 Report

Quoted By: >>14026448 >>14026647

>>14026398
0.

Anonymous

Anonymous Wed 29 Dec 2021 01:40:42 No.14026410 Report

Quoted By: >>14028753

It's an empty product so it's the neutral element of multiplication.

Anonymous

Anonymous Wed 29 Dec 2021 01:41:36 No.14026413 Report

Quoted By: >>14026422 >>14026448 >>14029974

>>14026384
a^0 = a^(1-1) = (a^1)*(a^(-1)) = a/a = 1
qed

Anonymous

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Anonymous Wed 29 Dec 2021 01:43:59 No.14026422 Report

Quoted By: >>14026443

>>14026413

Anonymous

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Anonymous Wed 29 Dec 2021 01:51:54 No.14026443 Report

Quoted By:

>>14026422
aint gonna type that latex for you kiddo

Anonymous

Anonymous Wed 29 Dec 2021 01:52:17 No.14026448 Report

Quoted By: >>14026498 >>14029801

>>14026407
this, also a^-1 should be -a which takes care of >>14026413

Anonymous

Anonymous Wed 29 Dec 2021 01:59:17 No.14026472 Report

Quoted By: >>14026860

>>14026384
Because 1 is the smallest natural, and raising something to 0 does not mean the value disappears, something that is always deeply problematic in math. It simply lessens to the smallest unit.

Anonymous

Anonymous Wed 29 Dec 2021 02:04:42 No.14026498 Report

Quoted By: >>14026541

>>14026448
What are you on? Where are you getting -a?

Anonymous

Anonymous Wed 29 Dec 2021 02:20:49 No.14026541 Report

Quoted By: >>14026654 >>14028821 >>14028975

>>14026498
what else would a^-1 be? it's -1 many a's

El Arcón

El Arcón Wed 29 Dec 2021 02:30:13 No.14026566 Report

Quoted By: >>14026633

a^0 times a is equal to a^1. This rule for manipulating exponents requires that a^0 is the multiplicative identity.

Anonymous

Anonymous Wed 29 Dec 2021 02:38:36 No.14026586 Report

Quoted By:

>>14026384
Because a travels to another dimension to recreate itself by itself thus a = itself which is in this case 1

A black hole is zero which creates a replica nt of the number times zero in a new plain thus a x 0 = a

Anonymous

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Anonymous Wed 29 Dec 2021 02:40:41 No.14026589 Report

Quoted By:

>true by definition

Anonymous

Anonymous Wed 29 Dec 2021 02:41:59 No.14026592 Report

Quoted By:

If your math teacher told you "IT JUST DOES" as the proof, she needs to be fired. Yes I know it's a she because no man would be that retarded

Anonymous

Anonymous Wed 29 Dec 2021 02:45:43 No.14026604 Report

Quoted By: >>14027661

>>14026384
a^3=a^4/a
a^2=a^3/a
a^1=a^2/a
a^0=a^1/a
a^-1=a^0/a
a^-2=a^-1/a
a^-3=a^-2/a

Anonymous

Anonymous Wed 29 Dec 2021 02:48:47 No.14026620 Report

Quoted By:

assume a != 0
a^b === e^(b*log(a))
(for mathlets triple equals means "is defined to be")
a^0 = e^0 = e^(0i) = cos(0) + isin(0) = 1

Anonymous

Anonymous Wed 29 Dec 2021 02:50:11 No.14026627 Report

Quoted By: >>14026634

>>14026384
Exponentiation is multiplication which has a defined identity of 0.

Anonymous

Anonymous Wed 29 Dec 2021 02:50:45 No.14026633 Report

Quoted By: >>14026664 >>14026679 >>14027311

>>14026566
>El Acron
Stopped reading. Infinity is not a number.

Anonymous

Anonymous Wed 29 Dec 2021 02:51:12 No.14026634 Report

Quoted By:

>>14026627
of 1. Exponentiation is multiplication which has an identity of 1.

Anonymous

Anonymous Wed 29 Dec 2021 02:54:03 No.14026647 Report

Quoted By:

>>14026407
so log(0) = 0?

Anonymous

Anonymous Wed 29 Dec 2021 02:55:22 No.14026654 Report

Quoted By: >>14026844

>>14026541
a^-1 = 1/a
Where is the "-1 many as"?

Anonymous

Anonymous Wed 29 Dec 2021 02:56:02 No.14026655 Report

Quoted By:

>Hello I would like a^0 apples please

Absolute fools

Anonymous

Anonymous Wed 29 Dec 2021 02:57:13 No.14026664 Report

Quoted By: >>14026670 >>14026684

>>14026633
You're fucking stupid lib take the vaccine and die

Anonymous

Anonymous Wed 29 Dec 2021 02:58:06 No.14026670 Report

Quoted By:

>>14026664
I did. Quads I survive.

Anonymous

Anonymous Wed 29 Dec 2021 02:59:21 No.14026679 Report

Quoted By: >>14026684

>>14026633
retard, he is one of the most knowledgeable posters on /sci.

Anonymous

Anonymous Wed 29 Dec 2021 03:01:03 No.14026684 Report

Quoted By: >>14026741

>>14026664
>>14026679
Also a prolific samefagger

Anonymous

Anonymous Wed 29 Dec 2021 03:11:43 No.14026737 Report

Quoted By: >>14027338

>>14026384
exponents are 1 multiplied by the base number however many times.
2^2 = 4 (1*2*2)
2^-1 = 0.5 (1/2)
so when the exponent is 0 you dont do anything to the 1

Anonymous

Anonymous Wed 29 Dec 2021 03:13:10 No.14026741 Report

Quoted By:

>>14026684
I'm a girl btw

Anonymous

Anonymous Wed 29 Dec 2021 03:41:25 No.14026830 Report

Quoted By:

>>14026384
12 = 2*2*3, how many times do I multiply by the prime number 5? 0 times. which keeps the number the same, multiplying it by 1

Anonymous

Anonymous Wed 29 Dec 2021 03:46:21 No.14026844 Report

Quoted By: >>14027288

>>14026654
>said the 2^-1 -wit

Anonymous

Anonymous Wed 29 Dec 2021 03:50:51 No.14026860 Report

Quoted By:

>>14026472
0 is a natural number faggot

Anonymous

Anonymous Wed 29 Dec 2021 06:06:31 No.14027288 Report

Quoted By:

>>14026844
Are you tooker? Damn are you really this shortsighted on math?

El Arcón

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El Arcón Wed 29 Dec 2021 06:13:13 No.14027311 Report

Quoted By: >>14029008

>>14026633

Anonymous

Anonymous Wed 29 Dec 2021 06:26:45 No.14027338 Report

Quoted By: >>14027356

>>14026737
This one is a friendly explanation.

El Arcón

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El Arcón Wed 29 Dec 2021 06:37:11 No.14027356 Report

Quoted By:

>>14027338
>friendly explanation.

El Arcón

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El Arcón Wed 29 Dec 2021 06:38:13 No.14027360 Report

Quoted By:

El Arcón

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El Arcón Wed 29 Dec 2021 06:39:01 No.14027362 Report

Quoted By:

El Arcón

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El Arcón Wed 29 Dec 2021 06:51:30 No.14027391 Report

Quoted By:

El Arcón

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El Arcón Wed 29 Dec 2021 06:52:38 No.14027394 Report

Quoted By:

El Arcón

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El Arcón Wed 29 Dec 2021 06:53:39 No.14027400 Report

Quoted By:

Anonymous

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Anonymous Wed 29 Dec 2021 08:40:13 No.14027661 Report

Quoted By:

>>14026604
Nice....

Anonymous

Anonymous Wed 29 Dec 2021 08:59:47 No.14027721 Report

Quoted By:

>>14026384
I would like to speak to the manager of Math

Anonymous

Anonymous Wed 29 Dec 2021 09:15:53 No.14027755 Report

Quoted By: >>14027836

>>14026384
Counter proof:
>Because.... uhhhhh... IT JUST DOESN'T. TRUST ME

Anonymous

Anonymous Wed 29 Dec 2021 09:55:36 No.14027836 Report

Quoted By:

>>14027755
this, but unironically

Anonymous

Anonymous Wed 29 Dec 2021 10:53:26 No.14027937 Report

Quoted By:

>>14026384
a = a^1 = a^(1+0) = a * a^0
1 = a^0

Anonymous

Anonymous Wed 29 Dec 2021 12:51:10 No.14028155 Report

Quoted By: >>14028167

>>14026384
a = 1^(1/0)
why is this true?

Anonymous

Anonymous Wed 29 Dec 2021 12:54:00 No.14028167 Report

Quoted By:

>>14028155
MATH BROS WE GOT TOO COCKY

Anonymous

Anonymous Wed 29 Dec 2021 12:58:12 No.14028177 Report

Quoted By:

Isn't it really a^0 = 1a?
So by saying ^0 you're saying you're not doing powers at the moment.

Anonymous

Anonymous Wed 29 Dec 2021 15:15:08 No.14028684 Report

Quoted By:

>>14026384
a^x = exp(x*lna)
Now do the power series expansion and tada.

Anonymous

Anonymous Wed 29 Dec 2021 15:17:10 No.14028697 Report

Quoted By: >>14030283

>>14026384
$ 0^0=1 0/0=1 $

Anonymous

Anonymous Wed 29 Dec 2021 15:18:57 No.14028705 Report

Quoted By:

>>14026384
Basado

Anonymous

Anonymous Wed 29 Dec 2021 15:35:14 No.14028753 Report

Quoted By:

>>14026410
>The only smart person ITT.

Anonymous

Anonymous Wed 29 Dec 2021 15:43:27 No.14028781 Report

Quoted By:

>>14026384
math is just a symbolic system that based on set of rules.
its like asking why OP is always a massive faggot, its just is...

Anonymous

Anonymous Wed 29 Dec 2021 15:53:47 No.14028821 Report

Quoted By: >>14028975

>>14026541
exponentiation = multiple multiplications
negative exponentiation = multiple divisions
negatives are inverse operations

Anonymous

Anonymous Wed 29 Dec 2021 16:26:25 No.14028975 Report

Quoted By: >>14029043

>>14028821
>>14026541
Thats the definition for integers, otherwise factorial and exponents would be undefined for nonintegers.
noninteger exponentiation is defined with a^b=e^(b*log(a))

Anonymous

Anonymous Wed 29 Dec 2021 16:33:37 No.14029008 Report

Quoted By:

>>14027311
>numbers correspond to a singular defined quantity
>infinity doesn't correspond to singular defined quantity
Therefore infinity is not a number

Anonymous

Anonymous Wed 29 Dec 2021 16:41:02 No.14029043 Report

Quoted By: >>14029086

>>14028975 >>14028975
noninteger exponentation is defined as $x^y = \sup\{ x^q \mid q \in \mathbb{Q}, q \leq y \}$ where $x^{\frac{a}{b}} = \sqrt{x^a}$ where $\sqrt[n]{x} = \sup\{ y \in \mathbb{R} \mid y^n \leq x \}$

Anonymous

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Anonymous Wed 29 Dec 2021 16:49:06 No.14029086 Report

Quoted By:

>>14029043
Nice but not sure this works for irrationals but more importantly doesn't work for complex valued qualities whereas the previous one does

Anonymous

Anonymous Wed 29 Dec 2021 19:29:45 No.14029801 Report

Quoted By:

>>14026448
how would you differentiate -a and a^-1 after the change is made?

Anonymous

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Anonymous Wed 29 Dec 2021 19:45:04 No.14029874 Report

Quoted By:

>>14026384
a^x approaches 1 on both sides, easy to see how it's 1

Anonymous

Anonymous Wed 29 Dec 2021 20:06:52 No.14029974 Report

Quoted By:

>>14026413
If a?0

Anonymous

Anonymous Wed 29 Dec 2021 21:08:35 No.14030283 Report

Quoted By:

>>14028697
That's just true though.

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