Let the sidelength of the square be
Let the angle of the triangle with a sidelength be
Let the angle of the triangle with a sidelength be
Then for , area of the square,
By the Cosine Rule,
Applying the cosine function on both sides and rearranging gives,
what did i do wrong? By squaring both sides, I expected the equation to produce extraneous solution for A, but none of them is even positive real
