/sci/ - Science & Math » Thread #13887969

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Anonymous Thu 25 Nov 01:38:48 2021 No.13887969 View Reply Original Report

Quoted By: >>13887992 >>13888010 >>13888606 >>13889020

Is there really no Quotient Rule for integration in Calculus?

Anonymous

Anonymous Thu 25 Nov 2021 01:52:03 No.13887992 Report

Quoted By: >>13888065

>>13887969
retard

Anonymous

Anonymous Thu 25 Nov 2021 01:58:43 No.13888010 Report

Quoted By: >>13889864

>>13887969
$\int \frac{f(x)g'(x) - f'(x)g(x)}{g(x)^2} dx = \frac{f(x)}{g(x)} + C$

Anonymous

Anonymous Thu 25 Nov 2021 02:38:37 No.13888065 Report

Quoted By:

>>13887992
?

Anonymous

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Anonymous Thu 25 Nov 2021 07:07:38 No.13888606 Report

Quoted By:

>>13887969
lmfao all you had to do was integrate the derivative quotient rule

Anonymous

Anonymous Thu 25 Nov 2021 12:03:35 No.13889020 Report

Quoted By:

>>13887969
just integrate by parts retard

Anonymous

Anonymous Thu 25 Nov 2021 18:41:36 No.13889864 Report

Quoted By:

>>13888010
Well, the "integration by parts" way to write it would be:
$\int f(x)\frac{g'(x)}{g(x)^2} dx = \frac{f(x)}{g(x)} + \int \frac{f'(x)}{g(x)} dx$
Or maybe:
$\int \frac{f'(x)}{g(x)} dx = \int f(x)\frac{g'(x)}{g(x)^2} dx - \frac{f(x)}{g(x)}$
Neither seems particularly useful.

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