Proof that i = 0

No.13799964 ViewReplyOriginalReport
We begin with Euler's identity
>e^(i*pi) = -1
Square both sides
>(e^(i*pi))^2 = (-1)^2
>e(2*i*pi) = 1
Therefore
>2*i*pi = 0
2 is not 0, pi is not 0, so i has to be 0.

q.e. fucking d.