E=mc^2 and Ek=1/2mv^2
No.13729115 ViewReplyOriginalReport
Quoted By: >>13729865 >>13731264 >>13731272
If E=mc^2 and Ek=1/2mv^2, does that mean that mc^2=1/2mv^2 (since kinetic energy Ek is only a specialized case of energy E), what are the implications of this?