/sci/ - Science & Math » Thread #13728280

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Anonymous Fri 08 Oct 08:04:02 2021 No.13728280 View Reply Original Report

Quoted By: >>13728294 >>13728297 >>13728339 >>13728347 >>13728364 >>13728592

If 0.999... = 1 then doesnt every number equal the 0.000...1 of itself?
So 1 = 1.000...1?
If so then nothing equals anything

Anonymous

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Anonymous Fri 08 Oct 2021 08:06:21 No.13728286 Report

Quoted By:

>If 0.999... = 1 then doesnt every number equal the 0.000...1 of itself?

Anonymous

Anonymous Fri 08 Oct 2021 08:11:42 No.13728294 Report

Quoted By:

>>13728280
Yes.

Anonymous

Anonymous Fri 08 Oct 2021 08:12:42 No.13728297 Report

Quoted By:

>>13728280
You're right, math is a lie

Anonymous

Anonymous Fri 08 Oct 2021 08:18:32 No.13728311 Report

Quoted By:

based this is why infinity should be banned

Anonymous

Anonymous Fri 08 Oct 2021 08:32:27 No.13728339 Report

Quoted By:

>>13728280
>0.000...1
doesn't exist

Anonymous

Anonymous Fri 08 Oct 2021 08:36:57 No.13728347 Report

Quoted By: >>13728350 >>13728359

>>13728280
>If so then nothing equals anything
What do you mean?

Anonymous

Anonymous Fri 08 Oct 2021 08:37:57 No.13728350 Report

Quoted By:

>>13728347
u know what he means stop arguing in bad faith infinity schizo

Anonymous

Anonymous Fri 08 Oct 2021 08:41:54 No.13728359 Report

Quoted By:

>>13728347
I'm guessing OP means something like this
0.000...0=0.000...1=0.000...2 and when you keep going 0=1 and so on

Anonymous

Anonymous Fri 08 Oct 2021 08:44:16 No.13728364 Report

Quoted By:

>>13728280
>so then nothing equals anything
Woah chief you kind of went from infinitesimal to infinite in one step there

Anonymous

Anonymous Fri 08 Oct 2021 11:25:14 No.13728592 Report

Quoted By:

>>13728280
0.1=10^-1
0.01=10^-2
0.001=10^-3
:
0.0...1=10^-inf=0

Anonymous

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Anonymous Fri 08 Oct 2021 11:25:51 No.13728593 Report

Quoted By:

>10^-inf

Anonymous

Anonymous Fri 08 Oct 2021 11:30:27 No.13728603 Report

Quoted By:

$\displaystyle 0. \bar{0}1 = \lim_{n \to \infty} 0. \underbrace{0 \dots 0}_{n ~ \text{times}}1 = \lim_{n \to \infty} \left [ \left ( \sum_{k=1}^n \dfrac{0}{10^k} \right ) + \dfrac{1}{10^{n+1}} \right ] =0 $

Anonymous

Anonymous Fri 08 Oct 2021 11:31:38 No.13728604 Report

Quoted By:

>if you finish the infinite task, you will get this number, bro
>trust me, the limit says so

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