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Anonymous Thu 07 Oct 06:42:31 2021 No.13724147 View Reply Original Report

Quoted By: >>13724168 >>13724340 >>13724361 >>13724830 >>13727488 >>13728050

First challenge:
Solve and explain pic related

Mohan

Mohan Thu 07 Oct 2021 06:53:59 No.13724168 Report

Quoted By:

>>13724147
4 seems right, but can't say four-shour

Anonymous

Anonymous Thu 07 Oct 2021 09:03:47 No.13724340 Report

Quoted By: >>13724352

>>13724147
Actual midwit here, so correct me if i'm wrong. 4, using very simple logic. Triangles take 3 blue dots, cube and retangle take 4 blue dots.

Anonymous

Anonymous Thu 07 Oct 2021 09:10:57 No.13724352 Report

Quoted By:

>>13724340
Also, there is 2 sequences which are horizontal(first and 5th), and second and third sequences are in an inclined angle. So, by looking at the last sequence, it already gives a hint about the answer. My reasoning looks pretty dumb, but 4 looks like the answer.

Anonymous

Anonymous Thu 07 Oct 2021 09:16:10 No.13724361 Report

Quoted By: >>13724593

>>13724147
If the box only contains 4-sided shapes then there will be 4 dots. If the box only contains 3-sided shapes then there will be 3 dots.

Answer: 1

Anonymous

Anonymous Thu 07 Oct 2021 11:33:18 No.13724593 Report

Quoted By:

>>13724361
and a box containing both a square and triangle are incongruent and have no residual characteristic.

Anonymous

Anonymous Thu 07 Oct 2021 13:10:38 No.13724830 Report

Quoted By: >>13724858

>>13724147
I can see at least two reasonable answers. I don't think these newer Raven's kits underwent as much R&D.

ANSWER ONE: 1. If and only if all the red shapes are the same, there's a row of blue circles, with the number of circles equal to the number of sides of the similar red shape.

ANSWER TWO: 4. A row of blue circles, when present, must govern an axis of symmetry.

Anonymous

Anonymous Thu 07 Oct 2021 13:22:42 No.13724858 Report

Quoted By: >>13724876

>>13724830
btw, I prefer 1 because it takes into account the number of circles, but I don't see how 4 can be eliminated with strict logic, because there's no necessary rule that the number of circles matters or must have a certain amount of coverage. In each case, the line of blue circles is sufficient to indicate an axis of symmetry.

Anonymous

Anonymous Thu 07 Oct 2021 13:28:57 No.13724876 Report

Quoted By:

>>13724858
I mean, there's an axis of symmetry in the second box not indicated with a blue line, but this can be discarded on account of the different red shapes -- or with emphasis on "when present" in "A row of blue circles, when present, must govern an axis of symmetry."

So 1 is probably the expected answer, and I find it more satisfying, but 4 is also valid from the standpoint of strict logic.

Anonymous

Anonymous Fri 08 Oct 2021 02:49:56 No.13727488 Report

Quoted By:

>>13724147
No pattern detected.

Anonymous

Anonymous Fri 08 Oct 2021 06:11:10 No.13728050 Report

Quoted By:

>>13724147
I would need to practice a fewer easier questions of this variety. There is too many ways to unfold this. In terms of the squares in numbered order,
>(1)(2)=3 -> (4)(5)=6 (isomorphism)
>(1)(2)=3, (2)(3)=4, (3)(4) = 5 (or some other generative series)
>1:4, 2:5, 3:6 (or some other analogous combination)
>1o->2 : 2o->3 : 3o->4 : 4o->5 : 5o->6 (like some arithmetic series)
This doesn't even get into subdividing elements in the picture. I would like to see how various simple logics play out in this form.

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