Quoted By:
[latex]P(getting\ at\ least\ three\ 3* characters)\\
=1-P(getting\ two\ 3* characters)-P(getting\ one\ 3* character)-P(getting\ no\ 3* characters)\\
=1-\binom{10}{2}(0.02^2*0.98^8)-\binom{10}{1}(0.02* 0.98^9)-\binom{10}{0}*(0.98^{10}) \\
\approx 0.086%[/latex]
