/sci/ - Science & Math » Thread #13515939

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Anonymous Fri 13 Aug 23:21:05 2021 No.13515939 View Reply Original Report

Quoted By: >>13515978 >>13516027 >>13516464 >>13516479 >>13516968

I have a function in mind, but don't know notation. If you like .999... = 1 BS, this is your thing too.

There exists a function G where each real number x ending in an even digit has a value of 1, and each real number ending in an odd digit has a value of -1.

Pic unrelated.

Anonymous

Anonymous Fri 13 Aug 2021 23:31:53 No.13515978 Report

Quoted By:

>>13515939
lol, learn to code, creating random and arbitrary functions isnt discovering anything

Anonymous

Anonymous Fri 13 Aug 2021 23:33:45 No.13515990 Report

Quoted By:

this is called an "indicator function"

Anonymous

Anonymous Fri 13 Aug 2021 23:41:18 No.13516027 Report

Quoted By: >>13516121

>>13515939
Your function is not properly defined. You get different results in base 10 or base 2 or whatever. Last digit can be anything for the same number.

Anonymous

Anonymous Sat 14 Aug 2021 00:10:45 No.13516121 Report

Quoted By: >>13517512

>>13516027
Your post does not make sense to me, please elaborate anon

Anonymous

Anonymous Sat 14 Aug 2021 02:03:20 No.13516464 Report

Quoted By:

>>13515939
y = cos (x * pi)
You're welcome

Anonymous

Anonymous Sat 14 Aug 2021 02:10:12 No.13516479 Report

Quoted By:

>>13515939
How does the function even start? With whole numbers only? For example 3.1? 3.2? 3.3? 3.02? 3…? Would be a bunch of dots in the with value 1 or -1 depending on how far you zoom in the scale of your graph

Anonymous

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Anonymous Sat 14 Aug 2021 06:07:21 No.13516964 Report

Quoted By: >>13517517

i thought of a fun problem the other day:
let $f(x):\mathbb{R}\rightarrow\mathbb{R}$ be a function such that if $n\in\mathbb{N}$ , and the digits of $n$ from most to least significant are $n_0, n_1, n_2, \cdots$ , then $f(x)=2^{n_0}+3^{n_1}+5^{n_2}+7^{n_3}+11^{n_4}+\cdots$ , ignoring any leading zeros. for example, $f(8675309)=2^8+3^6+5^7+7^5+11^3+13^0+17^9=118587973746$ .
show that there is no finite polynomial expression for $f(x)$

Anonymous

Anonymous Sat 14 Aug 2021 06:09:01 No.13516968 Report

Quoted By:

>>13515939
>here exists a function G where each real number x ending in
Not every real number has a finite decimal representation.

Anonymous

Anonymous Sat 14 Aug 2021 10:21:48 No.13517512 Report

Quoted By:

>>13516121
Number 12 in base 10 is written as "12" with las digit even and in base 7 is written as "15" which has last digit odd
12=1x10+2
15=1x7+5

Anonymous

Anonymous Sat 14 Aug 2021 10:27:09 No.13517517 Report

Quoted By:

>>13516964
f(10^k) is the kth prime and there is no polynomial which sends an exponentially increasing sequence to a logarithmically increasing sequence

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