>>13427868Equivalently
>What is the chance you will be correct if you randomly choose an answer to this question? >A:25%, B:50%, C:0%, D:25% Here's ONE interesting way to look at this problem
>What is the probability that you've chosen the correct answer, if you randomly choose one of the four possible answers to this question: A, B, C, and DIF WE ASSUME there exists a correct answer among the options, then P(correct) = 1/(# of distinct options).
[----Like, say there 100 circles where you can bubble in your answer; 36 bubbles are X, 22 bubbles are Y, and 42 bubbles are Z.
Then P(correct) = 1/3(#X/100) + 1/3(#Y/100) + 1/3(#Z/100) = 1/3(100/100) = 1/3.
----Or if your friend chooses a number from 1-3, what is the probability you randomly choose the same number:
P(correct) = {he chooses 1} * {you choose 1} + {he chooses 2} * {you choose 2} + {he chooses 3} * {you choose 3}
= 1/3(1/3) + 1/3(1/3) + 1/3(1/3) = 1/3(3/3) = 1/3.
----The same is if a prize is behind one of three doors and you gotta choose one door (1/3).]
Since there are three distinct options {"0%", "25%", "50%"}, the probability you will be randomly correct is 1/3. The same would happen if the options were {"dog", "cat", mouse"}. Thus, the answer would be 1/3, and not something like A:25% or C:0%. In this line of thinking, the question isn't asking you to choose a letter, but simply the verbatim "what is the chance" or probability.
