the speed of light is energy over radius
when you move the terms around:
R = E / C
The radius of the universe (relative to an object) is equal to the object's total energy divided by the speed of light
See what you do now is approximate (lol us engineers and approximation) the energy into kinetic energy and then you approximate the speed to the speed of light so you get
R = mc^2 / 2c = mc/2
mc/2 is the radius of the observable universe in reference to the object that is observing it.
Another way is:
E = mc^2
R = mc^2/c = mc
We get double as much because E = Ek + Ep but since we ignored the potential energi in the first approach, it's twice as small.
What does this all mean?ii means that the universe does not have an absolute size